我一直在做这个项目。主要目的是计算有多少单词不包含字母'B‘或'C’。给定文件有0;1000行。每一行包含6列。
前两列包含1;20个字符的字符串。字符可以是字母、数字和空格。
3-5列包含范围为- 100;100的整数。第6列包含范围内的实数- 9.99;9.99,小数点后只有两位数。
每一段我用分号分隔。
文件示例:
helloA;lB;lC;lD;lE;lF
A11;bas morning;0;0;5;1.15
B12; Hello WoRlD;-100;11;78;1.33
B11;table;10;0;55;-2.44
C1;OakWood;0;8;17;3.77任务:计算前两列中不包含字母'B‘或'C’的单词(单词是一个或多个没有‘(空格)的符号)。然后打印那个整数。
我已经完成了大部分任务。我已经从命令行读取了file的名称,读取了该文件,并将整数逐出。但我坚持了一件事。我真的不明白如何逐个检查每一个字。我几乎每次都得到错误的答案。
Input: ( a A a a aba aca;BA A C BA a;1;1;1;1.00) - without brackets.
Output: 6到目前为止我的代码
org 100h
%include 'yasmmac.inc'
section .text
startas:
macPutString 'Write outpu file name', crlf, '$'
; Reading file from command line
.commandLine:
mov bx, 82h
mov si, 0h
jmp .checkInputFile
; Turns it into ASCIIZ
.checkInputFile:
mov cl, [bx+si]
cmp cl, 20h
jl .addZero
inc si
jmp .checkInputFile
.addZero:
mov byte [bx+si], 0h
xor si, si
; Saving writing file
mov al, 128
mov dx, writingFile
call procGetStr
macNewLine
; Open reading file
mov dx, bx
call procFOpenForReading
jnc .writingFileIsOpened
macPutString 'Error while opening reading file', '$'
exit
; Atidarome rasymo faila
.writingFileIsOpened:
mov [readingDescriptor], bx
mov dx, writingFile
call procFCreateOrTruncate
jnc .openWritingFile
macPutString 'Error while opening writing file', '$'
jmp .writingError
; Save writing descriptor
.openWritingFile:
mov [writingDescriptor], bx
; Reads first line
call procReadLine
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
; Main loop
.whileNotEndOfFile:
xor di, di
xor si, si
call procReadLine
; Check first two columns
;mov al, ';'
mov di, line
mov al, [di]
cmp al, ' '
je .nextWord
cmp al, ';'
je .nextWord
; Checking words
.checkWord:
mov al, [di]
inc di
cmp al, byte 'B'
je .nextWord
cmp al, byte 'b'
je .nextWord
cmp al, byte 'C'
je .nextWord
cmp al, byte 'c'
je .nextWord
cmp al, byte ' '
je .addNumber
cmp al, byte ';'
je .semicolon
jmp .checkWord
.nextWord:
call procNextWord
jmp .checkWord
.semicolon:
call procAddNumber
inc si
cmp si, 0x2
je .skipLine
jmp .nextWord
.addNumber:
call procAddNumber
jmp .nextWord
; If this is not the end of file, repeat loop
.skipLine:
cmp [readLastLine], byte 0
je .whileNotEndOfFile
; Hexadecimal convertion to decimal
mov dx, lineCount
mov ax, [lineCount]
call procUInt16ToStr
call procPutStr
macNewLine
mov si, dx
.writingToFile:
lodsb
cmp al, 0
jne .writingToFile
sub si, dx
lea cx, [si-1]
mov bx, [writingDescriptor]
mov ah, 40h
int 21h
; Closing Files
.end:
mov bx, [writingDescriptor]
call procFClose
.writingError:
mov bx, [readingDescriptor]
call procFClose
macPutString 'Program ends', crlf, '$'
exit
%include 'yasmlib.asm'
; void procReadLine()
; Read line to buffer ‘eilute’
procReadLine:
push ax
push bx
push cx
push si
mov bx, [readingDescriptor]
mov si, 0
.loop:
call procFGetChar
; End if the end of file or error
cmp ax, 0
je .endOfFile
jc .endOfFile
; Putting symbol to buffer
mov [line+si], cl
inc si
; Check if there is \n?
cmp cl, 0x0A
je .endOfLine
jmp .loop
.endOfFile:
mov [readLastLine], byte 1
.endOfLine:
mov [line+si], byte '$'
mov [lineLenght], si
pop si
pop cx
pop bx
pop ax
ret
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
procAddNumber:
push si
push ax
push bx
push cx
push dx
;lineCount++
mov ax, word [lineCount]
inc ax
mov [lineCount], ax
pop dx
pop cx
pop bx
pop ax
pop si
ret
procNextWord:
.loop:
inc di
mov al, [di]
cmp al, byte ' '
je .loop
jmp .t
.t:
cmp al, byte ';'
je .t2
jmp .return
.t2:
inc di
mov al, [di]
cmp al, byte ' '
je .t2
jmp .return
.return:
ret
section .data
readingDescriptor:
dw 0000
writingFile:
times 128 db 00
writingDescriptor:
dw 0000
readLastLine:
db 00
line:
db 64
times 66 db '$'
lineLenght:
dw 0000
lineCount:
times 128 db 00GITHUB: yasmmac.inc/yasmlib.span
任何帮助都会得到认可。
发布于 2022-11-17 22:12:11
完全从解决主要任务所需的思维过程开始,我得出如下结论:
; Main loop
.whileNotEndOfFile:
call procReadLine
mov si, 2 ; Do 2 columns
mov di, line
.skipSpaces:
mov al, [di]
inc di
cmp al, ' '
je .skipSpaces
cmp al, ';'
je .q3 ; It's trailing whitespace
dec di
.checkWord:
mov bx, 1 ; Assuming it will be a 'good' word
.q1:
mov al, [di]
inc di
cmp al, ' '
je .q2
cmp al, ';'
je .q2
or al, 32 ; LCase
cmp al, 'b'
jb .q1
cmp al, 'c'
ja .q1
xor bx, bx ; One or more invalid chars in current word
jmp .q1
.q2:
add [lineCount], bx ; BX=[0,1] Counting the 'good' words
cmp al, ';'
jne .skipSpaces
.q3:
dec si ; Next column ?
jnz .skipSpaces
.skipLine:
cmp [readLastLine], byte 0
je .whileNotEndOfFile标签lineCount不再是特别好的计数有效的单词,你不会说?
发布于 2022-11-17 18:15:06
mov al, [di] cmp al, ' ' \* je .nextWord \* cmp al, ';' \* je .nextWord \* .checkWord: mov al, [di] inc di
你正在失去字符串中的字符!
考虑一下。在“鼠标蝙蝠”中,.checkWord将获取空格字符,并将DI指向"b",,但然后procNextWord从增量DI开始,有效地从检查中删除"b“。程序的其余部分只看到"at“,并认为这是一个‘好’字。
procNextWord:
dec di ; Correcting DEC
.t1:
inc di
mov al, [di]
cmp al, ' '
je .t1
cmp al, ';'
jne .return
.t2:
inc di
mov al, [di]
cmp al, ' '
je .t2
.return:
ret如果您应用了建议的更正,那么还可以更改我用星号标记的行,然后写上:
cmp al, ' '
je .nextWordEx
cmp al, ';'
je .nextWordEx
...
.nextWordEx:
inc di
.nextWord:
call procNextWord
jmp .checkWord编辑
当您在一个单词中发现一个不合适的字符时,您需要跳过该单词的其余部分的,这不是procNextWord构建的目的!你需要另一个代码:
cmp al, 'B'
je .skipRemaining
cmp al, 'b'
je .skipRemaining
cmp al, 'C'
je .skipRemaining
cmp al, 'c'
je .skipRemaining
cmp al, ' '
je .addNumber
cmp al, ';'
je .semicolon
jmp .checkWord
.skipRemaining:
call procSkipRemaining
jmp .checkWord
...
procSkipRemaining:
mov al, [di]
cmp al, " "
je .return
cmp al, ";"
je .return
inc di
jmp procSkipRemaining
.return:
rethttps://stackoverflow.com/questions/74478881
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