调用的函数中的变量值不被更新。

Question

我正在试图计算总工资和工资率，但是当调用函数时，似乎没有更新pay_rate函数中的时间，即- 40，然后是- 4。请支持我。这是我的密码。

#include <iostream>
void pay_rate(float, float*);
void total_pay(float, float, float*);
int main() {
  float h, rate, total_salary = 0;
  printf("Input worked hours: ");
  scanf("%f", &h);
  pay_rate(h, &rate);
  // printf("%f", rate);
  total_pay(h ,rate,&total_salary);
  // printf("\n%f", total_salary);
  
}

void pay_rate(float hour, float* rate) {
  float temp = 0;
  if (0 < hour && hour <= 40)
  {
    temp = hour-40;
    *rate = 12.5;
    printf("\n%f", temp);
  } else if (0 < temp && temp <= 4) {
    *rate = 15;
    temp = temp-4;
    printf("\n%f", temp);
  } else if (temp > 0) {
    *rate = 20;
    printf("\n%f",temp);
  }
}

void total_pay(float hours, float rate, float* salary){
  *salary = rate * hours;
  
}

我尝试了一个临时变量，但它也不起作用。

Answer 1

如果希望在另一个函数中更新该值，则需要传递其地址。

#include <iostream>
void pay_rate(float*, float*);
void total_pay(float, float, float*);
int main() {
  float h, rate, total_salary = 0;
  printf("Input worked hours: ");
  scanf("%f", &h);
  pay_rate(&h, &rate);
  // printf("%f", rate);
  total_pay(h ,rate,&total_salary);
  // printf("\n%f", total_salary);
  
}

void pay_rate(float* hour, float* rate) {
  float temp = *hour;
  if (0 < *hour && *hour <= 40)
  {
    temp = (*hour)-40;
    *rate = 12.5;
    printf("\n%f", temp);
  } else if (0 < temp && temp <= 4) {
    *rate = 15;
    temp = temp-4;
    printf("\n%f", temp);
  } else if (temp > 0) {
    *rate = 20;
    printf("\n%f",temp);
  }
  *hour = temp;
}

void total_pay(float hours, float rate, float* salary){
  *salary = rate * hours;
  
}