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社区首页 >问答首页 >将重复对象的列表分组，而不将重复移到映射中。

问将重复对象的列表分组，而不将重复移到映射中。
EN

Stack Overflow用户
提问于 2022-11-02 19:01:39
回答 2查看 46关注 0票数 0

数组中有一个对象列表。每个对象都有一封电子邮件。

数组可能有重复的电子邮件，我想保留它们。

我想给出一个数字，比方说4，它应该把电子邮件分成4组，成一张地图，其中键就像组-1.在这个例子中，每个键中的值4是唯一的电子邮件，我将有一张5键的地图。

代码语言：javascript
复制
const emails=[{userId:'someuserid',email:'email1@gmail.com',password:'password1',recovery:'recovery1@gmail.com'},{userId:'someuserid',email:'email1@gmail.com',password:'password1',recovery:'recovery1@gmail.com'},{userId:'someuserid',email:'email10@gmail.com',password:'password10',recovery:'recovery10@gmail.com'},{userId:'someuserid',email:'email10@gmail.com',password:'password10',recovery:'recovery10@gmail.com'},{userId:'someuserid',email:'email2@gmail.com',password:'password2',recovery:'recovery2@gmail.com'},{userId:'someuserid',email:'email2@gmail.com',password:'password2',recovery:'recovery2@gmail.com'},{userId:'someuserid',email:'email3@gmail.com',password:'password3',recovery:'recovery3@gmail.com'},{userId:'someuserid',email:'email3@gmail.com',password:'password3',recovery:'recovery3@gmail.com'},{userId:'someuserid',email:'email4@gmail.com',password:'password4',recovery:'recovery4@gmail.com'},{userId:'someuserid',email:'email4@gmail.com',password:'password4',recovery:'recovery4@gmail.com'},{userId:'someuserid',email:'email5@gmail.com',password:'password5',recovery:'recovery5@gmail.com'},{userId:'someuserid',email:'email5@gmail.com',password:'password5',recovery:'recovery5@gmail.com'},{userId:'someuserid',email:'email6@gmail.com',password:'password6',recovery:'recovery6@gmail.com'},{userId:'someuserid',email:'email6@gmail.com',password:'password6',recovery:'recovery6@gmail.com'},{userId:'someuserid',email:'email7@gmail.com',password:'password7',recovery:'recovery7@gmail.com'},{userId:'someuserid',email:'email7@gmail.com',password:'password7',recovery:'recovery7@gmail.com'},{userId:'someuserid',email:'email8@gmail.com',password:'password8',recovery:'recovery8@gmail.com'},{userId:'someuserid',email:'email8@gmail.com',password:'password8',recovery:'recovery8@gmail.com'},{userId:'someuserid',email:'email9@gmail.com',password:'password9',recovery:'recovery9@gmail.com'},{userId:'someuserid',email:'email9@gmail.com',password:'password9',recovery:'recovery9@gmail.com'}]

const groupsMap = new Map()
let sequence = 0
let profilePrefix = 'none'
let pivotPrefix = 0
const prefix = 'group'
const bucketSize = 4
for (let index = 0; index < emails.length; index++) {
  const currentEmail = emails[index]?.email
  const prevEmail = emails[index - 1]?.email
  if (prevEmail && currentEmail === prevEmail) {
    if (
      groupsMap.has(`${prefix}-${pivotPrefix}`) &&
      groupsMap.get(`${prefix}-${pivotPrefix}`).length < bucketSize &&
      groupsMap
        .get(`${prefix}-${pivotPrefix}`)
        .findIndex((email) => currentEmail === email.email) === -1
    ) {
      groupsMap.get(`${prefix}-${pivotPrefix}`).push(emails[index])
      if (
        groupsMap.get(`${prefix}-${pivotPrefix}`).length === bucketSize
      ) {
        pivotPrefix++
      }
    } else {
      if (pivotPrefix > 0) {
        const nextPivot = pivotPrefix++
        groupsMap.get(`${prefix}-${nextPivot}`).push(emails[index])
      }
      sequence++
      profilePrefix = `${prefix}-${sequence}`
      groupsMap.set(profilePrefix, [emails[index]])
    }
  } else {
    if (groupsMap.has(`${prefix}-${pivotPrefix}`)) {
      if (
        groupsMap.get(`${prefix}-${pivotPrefix}`).length < bucketSize
      ) {
        groupsMap.get(`${prefix}-${pivotPrefix}`).push(emails[index])
        if (
          groupsMap.get(`${prefix}-${pivotPrefix}`).length ===
          bucketSize
        ) {
          pivotPrefix++
        }
      } else {
        sequence++
        groupsMap.set(`${prefix}-${sequence}`, [emails[index]])
      }
    } else {
      sequence++
      pivotPrefix = sequence
      profilePrefix = `${prefix}-${pivotPrefix}`
      groupsMap.set(profilePrefix, [emails[index]])
    }
  }
}

console.log(groupsMap)

// desired output below
Map(6) {
  'group-0' => [
    {
      userId: 'someuserid',
      email: 'email1@gmail.com',
      password: 'password1',
      recovery: 'recovery1@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email10@gmail.com',
      password: 'password10',
      recovery: 'recovery10@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email2@gmail.com',
      password: 'password2',
      recovery: 'recovery2@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email3@gmail.com',
      password: 'password3',
      recovery: 'recovery3@gmail.com'
    }
  ],
  'group-1' => [
    {
      userId: 'someuserid',
      email: 'email1@gmail.com',
      password: 'password1',
      recovery: 'recovery1@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email10@gmail.com',
      password: 'password10',
      recovery: 'recovery10@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email2@gmail.com',
      password: 'password2',
      recovery: 'recovery2@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email3@gmail.com',
      password: 'password3',
      recovery: 'recovery3@gmail.com'
    }
  ],
  'group-2' => [
    {
      userId: 'someuserid',
      email: 'email4@gmail.com',
      password: 'password4',
      recovery: 'recovery4@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email5@gmail.com',
      password: 'password5',
      recovery: 'recovery5@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email6@gmail.com',
      password: 'password6',
      recovery: 'recovery6@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email7@gmail.com',
      password: 'password7',
      recovery: 'recovery7@gmail.com'
    }
  ],
  'group-3' => [
    {
      userId: 'someuserid',
      email: 'email4@gmail.com',
      password: 'password4',
      recovery: 'recovery4@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email5@gmail.com',
      password: 'password5',
      recovery: 'recovery5@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email6@gmail.com',
      password: 'password6',
      recovery: 'recovery6@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email7@gmail.com',
      password: 'password7',
      recovery: 'recovery7@gmail.com'
    }
  ],
  'group-4' => [
    {
      userId: 'someuserid',
      email: 'email8@gmail.com',
      password: 'password8',
      recovery: 'recovery8@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email9@gmail.com',
      password: 'password9',
      recovery: 'recovery9@gmail.com'
    }
  ],
  'group-5' => [
    {
      userId: 'someuserid',
      email: 'email8@gmail.com',
      password: 'password8',
      recovery: 'recovery8@gmail.com'
    },
    {
      userId: 'someuserid',
      email: 'email9@gmail.com',
      password: 'password9',
      recovery: 'recovery9@gmail.com'
    }
  ]
}
javascript
EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2022-11-02 19:39:19

您可以将组保存为“桶”，并找到下一个放入电子邮件的桶。如果没有可用的桶，用电子邮件创建一个新的桶。

​

代码语言：javascript
复制
const emails=[{userId:'someuserid',email:'email1@gmail.com',password:'password1',recovery:'recovery1@gmail.com'},{userId:'someuserid',email:'email1@gmail.com',password:'password1',recovery:'recovery1@gmail.com'},{userId:'someuserid',email:'email10@gmail.com',password:'password10',recovery:'recovery10@gmail.com'},{userId:'someuserid',email:'email10@gmail.com',password:'password10',recovery:'recovery10@gmail.com'},{userId:'someuserid',email:'email2@gmail.com',password:'password2',recovery:'recovery2@gmail.com'},{userId:'someuserid',email:'email2@gmail.com',password:'password2',recovery:'recovery2@gmail.com'},{userId:'someuserid',email:'email3@gmail.com',password:'password3',recovery:'recovery3@gmail.com'},{userId:'someuserid',email:'email3@gmail.com',password:'password3',recovery:'recovery3@gmail.com'},{userId:'someuserid',email:'email4@gmail.com',password:'password4',recovery:'recovery4@gmail.com'},{userId:'someuserid',email:'email4@gmail.com',password:'password4',recovery:'recovery4@gmail.com'},{userId:'someuserid',email:'email5@gmail.com',password:'password5',recovery:'recovery5@gmail.com'},{userId:'someuserid',email:'email5@gmail.com',password:'password5',recovery:'recovery5@gmail.com'},{userId:'someuserid',email:'email6@gmail.com',password:'password6',recovery:'recovery6@gmail.com'},{userId:'someuserid',email:'email6@gmail.com',password:'password6',recovery:'recovery6@gmail.com'},{userId:'someuserid',email:'email7@gmail.com',password:'password7',recovery:'recovery7@gmail.com'},{userId:'someuserid',email:'email7@gmail.com',password:'password7',recovery:'recovery7@gmail.com'},{userId:'someuserid',email:'email8@gmail.com',password:'password8',recovery:'recovery8@gmail.com'},{userId:'someuserid',email:'email8@gmail.com',password:'password8',recovery:'recovery8@gmail.com'},{userId:'someuserid',email:'email9@gmail.com',password:'password9',recovery:'recovery9@gmail.com'},{userId:'someuserid',email:'email9@gmail.com',password:'password9',recovery:'recovery9@gmail.com'}]

const buckets = [];

const bucketSize = 4;

emails.forEach((e) => {
    const bucketIndex = buckets
      .map((b, i) => [b, i]) // zip with index
      .filter(([b]) => b.length < bucketSize) // buckets that aren't full
      .find(([b]) => b.every((u) => u.email !== e.email)); // bucket with available spot

    if (bucketIndex === undefined) buckets.push([e]); // create new bucket
    else buckets[bucketIndex[1]].push(e); // push to existing bucket by index
});

// zip with keys and create map
const map = new Map(buckets.map((b, i) => [`group-${i}`, b]));

// Just for display - Maps aren't displayed properly in the output yet
console.log(Object.fromEntries(Array.from(map)));
代码语言：javascript
复制
.as-console-wrapper { max-height: 100% !important }

​

票数 0
EN

Stack Overflow用户

发布于 2022-11-02 19:28:31

不确定，但如果您想要一组独特的电子邮件，这将给您4个对象与独特的电子邮件。

  • 首先我是过滤具有电子邮件唯一值的数组，而不是使用chunk函数，这是两个参数，一个是数组，另一个是数组的大小。
  • 块函数的过程如下，这里缺少的唯一东西**这里缺少的是关键，否则您将得到4个电子邮件块的数组对象。
  • 采用一个空数组来推送数组块，
  • 检查我们是否会有额外的块；如果具有块大小的数组长度的大小不等于零，则
  • ，如果数组长度的块大小为零，则必须计算
  • 的轮数，而不是只需将array.splice(0，size)推送到数组大小不等于零
  • (如果有轮时)，而只需推送数组直到其compelete未完成时，我们只需在arra.push(0，额外)的结果中添加额外的；
  • ，换句话说，将数组中的块按在数组中，直到数组的长度不等于额外，并且一旦数组长度与arra.push(0，extra )保持的额外相加一样；

​

代码语言：javascript
复制
const emails = [{
    userId: 'someuserid',
    email: 'email1@gmail.com',
    password: 'password1',
    recovery: 'recovery1@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email1@gmail.com',
    password: 'password1',
    recovery: 'recovery1@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email10@gmail.com',
    password: 'password10',
    recovery: 'recovery10@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email10@gmail.com',
    password: 'password10',
    recovery: 'recovery10@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email2@gmail.com',
    password: 'password2',
    recovery: 'recovery2@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email2@gmail.com',
    password: 'password2',
    recovery: 'recovery2@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email3@gmail.com',
    password: 'password3',
    recovery: 'recovery3@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email3@gmail.com',
    password: 'password3',
    recovery: 'recovery3@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email4@gmail.com',
    password: 'password4',
    recovery: 'recovery4@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email4@gmail.com',
    password: 'password4',
    recovery: 'recovery4@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email5@gmail.com',
    password: 'password5',
    recovery: 'recovery5@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email5@gmail.com',
    password: 'password5',
    recovery: 'recovery5@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email6@gmail.com',
    password: 'password6',
    recovery: 'recovery6@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email6@gmail.com',
    password: 'password6',
    recovery: 'recovery6@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email7@gmail.com',
    password: 'password7',
    recovery: 'recovery7@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email7@gmail.com',
    password: 'password7',
    recovery: 'recovery7@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email8@gmail.com',
    password: 'password8',
    recovery: 'recovery8@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email8@gmail.com',
    password: 'password8',
    recovery: 'recovery8@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email9@gmail.com',
    password: 'password9',
    recovery: 'recovery9@gmail.com'
  },
  {
    userId: 'someuserid',
    email: 'email9@gmail.com',
    password: 'password9',
    recovery: 'recovery9@gmail.com'
  }
];
let filterdResult = []; // to store unique email objects
// to filter emails object with unique email
let filterArray = emails.reduce((visitedEmailContainer, currentEmail) => {
  if (!visitedEmailContainer.includes(currentEmail.email)) {
    filterdResult.push(currentEmail);
    visitedEmailContainer.push(currentEmail.email);
    return visitedEmailContainer;
  }
  return visitedEmailContainer;
}, []);

function chunk(array, size) {
  /*
  - Take an empty array to push array chuncks
  - check if we will have extra chunks or not;
  - if array length's moudle with chunk size is not equal to zero that we have to count the number of rounds
  - if array length's moudle with chunk size is zero than we just need to push array.splice(0,size) till the array size is not equals to zero
  - if we have rounds , than we just need to push array till the rounds are not complete once its compelete we just need to add extra to result by arra.push(0,extra); 
  - In other words,push chunks in array till our array's length is not equal to extra and once array length is just as extra add remaining by arra.push(0,extra);
   */
  let result = [];
  let extra = array.length % size;
  if (extra == 0) {
    while (array.length !== 0) {
      result.push(array.splice(0, size));
    }
  } else if (extra) {
    while (array.length != extra) {
      result.push(array.splice(0, size));
    }
    result.push(array.splice(0, extra));
  }
  console.log(result);
  return result;
}
chunk(filterdResult, 4);

​

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：

https://stackoverflow.com/questions/74294413

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