MacOS VSCode Python安装程序

Question

当我运行除您的打印(“Hello，World")以外的其他任何内容时，终端将打印以下内容：

Traceback (most recent call last):
  File "/usr/local/Cellar/python@3.10/3.10.8/Frameworks/Python.framework/Versions/3.10/lib/python3.10/runpy.py", line 196, in _run_module_as_main
    return _run_code(code, main_globals, None,
  File "/usr/local/Cellar/python@3.10/3.10.8/Frameworks/Python.framework/Versions/3.10/lib/python3.10/runpy.py", line 86, in _run_code
    exec(code, run_globals)
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/__main__.py", line 39, in <module>
    cli.main()
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/../debugpy/server/cli.py", line 430, in main
    run()
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/adapter/../../debugpy/launcher/../../debugpy/../debugpy/server/cli.py", line 284, in run_file
    runpy.run_path(target, run_name="__main__")
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 321, in run_path
    return _run_module_code(code, init_globals, run_name,
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 135, in _run_module_code
    _run_code(code, mod_globals, init_globals,
  File "/Users/juliuseners/.vscode/extensions/ms-python.python-2022.16.1/pythonFiles/lib/python/debugpy/_vendored/pydevd/_pydevd_bundle/pydevd_runpy.py", line 124, in _run_code
    exec(code, run_globals)
  File "/Users/juliuseners/pythondir/Chapter 1.py", line 14, in <module>
    if dis>0:
TypeError: '>' not supported between instances of 'function' and 'int'

我解决不了这个问题，以前有没有人碰到过这个问题？

尝试手动改变路径使用家庭酿造的建议，但不知怎的，我不能让这个工作。

编辑:我添加了我试图在下面运行的代码：

import math
#The quadratic is luckily solved for all coefficients a,b,c except for a=0: this diqualifies the equation as quadratic. 
#I write the function based on following formula: x=(-b+/-sqrt(b^2-4*a*c))/2a

a=input("Enter a: ")
b=input("Enter b: ")
c=input("Enter c: ")

def findmyroots(a,b,c):
   dis=b*b-4*a*c
   sqrtdis=math.sqrt(abs(dis))
if dis>0:
    print("The roots are:")
    print((-b+sqrtdis)/(2*a))
    print((-b-sqrtdis)/(2*a))
elif dis==0:
    print("The roots are:")
    print((-b)/(2*a))
else:
    print("Roots are lateral")

if a==0:
    print("Write a real quadratic please..")
else:1
    findmyroots(a,b,c)

Answer 1

几个问题

1. 您的if块需要缩进才能在函数中。
2. 您的输入需要转换为数字，因为您不能对字符串类型进行计算。

相反：

import math
#The quadratic is luckily solved for all coefficients a,b,c except for a=0: this diqualifies the equation as quadratic. 
#I write the function based on following formula: x=(-b+/-sqrt(b^2-4*a*c))/2a

#Problem #2: These have to be numeric otherwise your math will throw an error. I'm wrapping in `int` as an example
a=int(input("Enter a: "))
b=int(input("Enter b: "))
c=int(input("Enter c: "))

def findmyroots(a,b,c):
    dis=b*b-4*a*c
    sqrtdis=math.sqrt(abs(dis))

    #Problem #1: Indentation. This all needs to be inside the function. 
    if dis>0:
        print("The roots are:")
        print((-b+sqrtdis)/(2*a))
        print((-b-sqrtdis)/(2*a))
    elif dis==0:
        print("The roots are:")
        print((-b)/(2*a))
    else:
        print("Roots are lateral")

if a==0:
    print("Write a real quadratic please..")
else:
    findmyroots(a,b,c)\

我不知道您对二次公式的实现是否正确(我已经关注了20+多年了)，但是这段代码将毫无错误地运行。