从嵌套字典中获取max值，如果相同，则返回两个键

Question

我有下面的字典

  {
    "match_1":{
        "home_team":2,
        "away_team":1
    },
    "match_2":{
        "home_team":1,
        "away_team":2
    },
    "match_3":{
        "home_team":1,
        "away_team":4}


}

我想总结主队和客队的进球，并找出哪支球队在总体上赢了，如果两者的得分是平局的话。我试着转换为tuple，并在lambda中使用max，但是当结果相同时，它失败了。

当前问题的所需输出：winner! away team

如果所有比赛的总目标相同：Draw

Answer 1

用这种狡猾的方法

d={
    "match_1":{
        "home_team":2,
        "away_team":1
    },
    "match_2":{
        "home_team":1,
        "away_team":2
    },
    "match_3":{
        "home_team":1,
        "away_team":4}


}
score = ((i["home_team"], i["away_team"]) for i in d.values())
t1,t2 = map(sum,zip(*score))
[["Away team","Home team"][t1>t2], "Draw"][t1==t2]

Answer 2

有许多选项可以这样做，其中一种方法是使用reduce函数

import functools

d = {
    "match_1": {"home_team": 2, "away_team": 1},
    "match_2": {"home_team": 1, "away_team": 2},
    "match_3": {"home_team": 1, "away_team": 4},
}

result = functools.reduce(
    lambda a, b: {
        "home_team": a["home_team"] + b["home_team"],
        "away_team": a["away_team"] + b["away_team"],
    },
    d.values(),
)

if result["home_team"] > result["away_team"]:
    print("winner! home_team")
elif result["away_team"] > result["home_team"]:
    print("winner! away_team")
else:
    print("Draw") 

Answer 3

我提供了一种处理这个问题的直觉方法。您可以尝试以下代码片段：

match =   {
    "match_1":{
        "home_team":2,
        "away_team":1
    },
    "match_2":{
        "home_team":1,
        "away_team":2
    },
    "match_3":{
        "home_team":1,
        "away_team":4}
}

home_team_score = 0
away_team_score = 0

for m in match:
    home_team_score += match[m]['home_team']
    away_team_score += match[m]['away_team']

if home_team_score > away_team_score:
    print("winner! home team")
elif home_team_score < away_team_score: 
    print("winner! away team")
else:
    print("Draw")