否则在程序中不执行

Question

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
      result = word
      if result == word:
         print(result)
      else:
         print("no result")

我使结果部分正常工作，但是每当输入错误的输入时，“无结果”输出就不会显示。

Answer 1

你为什么拿“开始”做比较？您可以像这样直接进行比较：

if word[0] == letter1 and word[1] == letter2:

做这样的事：

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
result = ""

for word in fruits:
   if word[0] == letter and word[1] == letter2:
      result = word
      break
  
if len(result) > 0:
         print(result)
else:
         print("no result")

Answer 2

你也可以像这样使用你的代码

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
flag = False
result=""
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
      flag = True
      result = word



if(flag == False):
   print("no result")
else:
   print(result)

Answer 3

您不需要使用嵌套的if和else条件。请记住，此代码将比较列表中的每一项，并显示每个结果，无论它们是否匹配。

fruits = ["mango", "banana", "apple", "yolk", "mulberry"]
letter = input("Enter the letter you want to search: ")
letter2 = input("Enter the second letter you want to search: ")
for word in fruits:
   if word[0].startswith(letter) and word[1].startswith(letter2):
         print(word)
   else:
      print("no result")