带有密码计数器的用户名和密码登录功能

Question

我已经学习了10天，这是我的第一个迷你项目，我被要求建立一个登录系统为员工和1个管理员，每个有一个简单的菜单多个选项。我必须创建一个包含10名员工的txt文件，每个员工都有不同的字符(id、用户名、工资.)。员工应输入用户名并保留密码为空，但管理员应输入预定义的用户名和密码，只允许5次错误尝试。但它不工作，为管理，当我输入错误的密码，它只是5次尝试，并声明密码限制达到。

with open('data.txt') as f:
    data = f.readlines()
dict = {}
for r in data:
    fields = r.split(",")
    id = fields[0]
    username = fields[1]
    date = fields[2]
    gender = fields[3]
    salary = fields[4]
    dict[username] = {"id": id, "name": username, "date of joining": date, "gender": gender, "salary": salary}#use username as primary key since it is what employee use to log in
def log_in(username,password):
    if username in dict.keys() and password=="":
        print("welcome employee,you will be redirected to employee menu")
        menu_employee()
    elif username not in dict.keys() and password=="" :
        print("Incorrect Username ")
    elif username in dict.keys() and password !="":
        print("Incorrect Username")
    else:
      for i in range(5,0,-1):
        if username == "admin" and password == "admin123123":
          print("welcome admin,you will be redirected to admin  menu")
          menu_admin()
        else:
          print("Incorrect Username and/or password, try again")
      if i==1:
        print("reached attempt limit")
      else:
        print("Incorrect Username and/or password, try again") 
username = input("Enter a username: ")#log in menu
password = input("Enter a password: ")

Answer 1

您必须在for循环中再次获得密码，否则程序将继续执行所有的迭代。当您使用输入时，程序将停止，直到用户插入新密码。

def log_in(username, password):
    print(dict.keys())
    if username in dict.keys() and password == "":
        print("welcome employee,you will be redirected to employee menu")
        menu_employee()
    elif username not in dict.keys() and password == "":
        print("Incorrect Username ")
    elif username in dict.keys() and password != "":
        print("Incorrect Username")
    else:
        for i in range(5, 0, -1):
            password = input("Enter a password: ")
            if username == "admin" and password == "admin123123":
                print("welcome admin,you will be redirected to admin  menu")
                menu_admin()
            else:
                print("Incorrect Username and/or password, try again")
        if i == 1:
            print("reached attempt limit")
        else:
            print("Incorrect Username and/or password, try again")

我还建议您从所阅读的输入中删除所有空格，以避免出现问题。

with open('data.txt') as f:
    data = f.readlines()
dict = {}
for r in data:
    # Remove all white spaces
    r = re.sub('\s+', '', r)
    fields = r.split(",")
    id = fields[0]
    username = fields[1]
    date = fields[2]
    gender = fields[3]
    salary = fields[4]
    dict[username] = {"id": id, "name": username, "date of joining": date, "gender": gender,
                      "salary": salary}  # use username as primary key since it is what employee use to log in

Answer 2

更新password块内的for值

    for i in range(5,0,-1):
        if username == "admin" and password == "admin123123":
            print("welcome admin,you will be redirected to admin  menu")
            menu_admin()
        else:
            print("Incorrect Username and/or password, try again")
            password = input("Enter a password: ")