bash脚本中的跳线

Question

后藤，在bash脚本中翻译成什么？

这是我的密码：

#!/bin/bash
read distro </etc/issue
echo $distro
if [[ "$distro" = "Debian GNU/Linux bookworm/sid n l" ]];
then
    goto Debian:
elif [[ "$distro" = "Ubuntu GNU/Linux bookworm/sid n l" ]];
then
    goto Ubuntu:
elif [[ "$distro" = "kali GNU/Linux bookworm/sid n l" ]];
then
    goto Kali:
elif [[ "$distro" = "Arch GNU/Linux bookworm/sid n l" ]];
then
    goto Arch:
else
    echo No suported OS detected some thing may not work
fi

Debian:
echo using Debian
sleep 5
exit

Ubuntu:
echo using Ubuntu
sleep 5
exit

Kali:
echo using kali
sleep 5
exit

Arch:
echo using Arch
sleep 5
exit

这是一段非常简单的代码，我甚至不知道我检查Linux发行版的方式是否有效

我尝试过从windows的批处理到Goto函数，但是它不能在Linux上工作，我将如何从一行跳到行？

Answer 1

我建议使用Switch-Case statement with fall-through。

所有“处理程序”都可以在将从开关调用的函数中定义：

#!/bin/bash

handleDebian() {
    echo "Using Debian"
}

handleUbuntu() {
    echo "Using Ubuntu"
}

handleKali() {
    echo "Using Kali"
}

handleArch() {
    echo "Using Arch"
}

handleUnknown() {
   echo "No suported OS detected some thing may not work"
}

read distro </etc/issue
case "${distro}" in
    *Debian*)   handleDebian() ;;
    *Ubuntu*)   handleUbuntu() ;;
    *kali*)     handleKali() ;;
    *Arch*)     handleArch() ;;
    *)          handleUnkown() ;;
esac

Answer 2

在这种情况下，我会选择一个更紧凑的case语句，例如：

read distro </etc/issue
echo $distro

case "${distro}" in
    *Debian*)    echo "Debian" ;;
    *Ubuntu*)    echo "Ubuntu" ;;
    *kali*)      echo "kali"   ;;
    *Arch*)      echo "Arch"   ;;
    *)           echo "No suported OS detected some thing may not work";;
esac

sleep 5