在Laravel中从关联数组中删除A~+-B重复

Question

我有一个包含几乎相同条目的关联数组，除了交换键值对之外：

[
    [
        "partnerA" => "Alice",
        "partnerB" => "Alfred"
    ],
    [
        "partnerA" => "Alfred",
        "partnerB" => "Alice"
    ],
    [
        "partnerA" => "Alfred",
        "partnerB" => "Brandon"
    ]
]

我将数组存储在Laravel collection中，并尝试使用->unique()。

  $partners = collect($array)->unique();

但是输出与输入的数组相匹配。

如何从数组中删除这样的副本，使每对都是唯一的，而不管键是否被交换？

期望的输出是：

[
    [
        "partnerA" => "Alice",
        "partnerB" => "Alfred"
    ],
    [
        "partnerA" => "Alfred",
        "partnerB" => "Brandon"
    ]
]

更新:到目前为止我尝试过的似乎是有效的.

$size = sizeof($partners);
for($i = 0; $i <= $size; $i++){
    $match = $partners[$i];
    $needle = ["partnerA" => $match["partnerB"], "partnerB" => $match["partnerA"]];
            
    if(in_array($needle, $partners)){
        unset($partners[$i]);
    }
}

Answer 1

对这些对进行排序，并将唯一键的值连接起来，然后根据结果进行筛选。

$unique_keys = array_keys(array_unique(array_map(
    function($a){
        sort($a);
        return implode("", $a);
    },
    $partners
)));

$res = array_filter(
    $partners,
    function($a)use($unique_keys) {
        return in_array($a, $unique_keys);
    },
    ARRAY_FILTER_USE_KEY
);

var_dump($res);

输出：

array(2) {
  [0]=>
  array(2) {
    ["partnerA"]=>
    string(6) "Alfred"
    ["partnerB"]=>
    string(5) "Alice"
  }
  [2]=>
  array(2) {
    ["partnerA"]=>
    string(6) "Alfred"
    ["partnerB"]=>
    string(7) "Brandon"
  }
}

Answer 2

尝尝这个

$results = [
[
    "partnerA" => "Alfred",
    "partnerB" => "Alice"
],
[
    "partnerA" => "Alfred",
    "partnerB" => "Alice"
]
];

$newArray = [];
foreach($results as $result) {
    if(is_array($result)) {
        foreach($result as $key => $output) {
            $newArray[$key] = $output;
        }
    }
}
print_r(array_unique($newArray));