我正在用快递生成器在Express.JS上建立一个站点,但在路由过程中遇到了麻烦。目前,每当向设置的另一条路由("/hook")发送GET请求时,我都会收到"error“视图和404消息。目前,正在工作的两条路由是"/“,它指向"index”,而"/users“则响应消息。我想知道为什么我要得到这个错误,因为其他工作。
下面是app.js文件:
var createError = require("http-errors");
var express = require("express");
var path = require("path");
var cookieParser = require("cookie-parser");
var logger = require("morgan");
var indexRouter = require("./routes/index");
var usersRouter = require("./routes/users");
var hookRouter = require("./routes/hook");
var app = express();
// view engine setup
app.set("views", path.join(__dirname, "views"));
app.set("view engine", "ejs");
app.use(logger("dev"));
app.use(express.json());
app.use(express.urlencoded({ extended: false }));
app.use(cookieParser());
app.use(express.static(path.join(__dirname, "public")));
app.use("/", indexRouter);
app.use("/users", usersRouter);
app.use("/hook", hookRouter);
// catch 404 and forward to error handler
app.use(function (req, res, next) {
next(createError(404));
});
// // error handler
app.use(function (err, req, res, next) {
// set locals, only providing error in development
res.locals.message = err.message;
res.locals.error = req.app.get("env") === "development" ? err : {};
// // render the error page
res.status(err.status || 500);
res.render("error");
});
module.exports = app;
这是索引路由器
var express = require('express');
var router = express.Router();
/* GET home page. */
router.get('/', function(req, res, next) {
res.render('index', { title: 'Express' });
});
module.exports = router;
下面是钩子路由器:
var express = require("express");
var router = express.Router();
/* GET hook page. */
router.get("/hook", function (req, res) {
res.send("Hook Page Works");
});
module.exports = router;
请让我知道有更多的信息我可以提供。谢谢!
发布于 2022-10-23 21:17:03
钩子路由器需要:
/* GET hook page. */
router.get("/", function (req, res) {
res.send("Hook Page Works");
});这是:
app.use("/hook", hookRouter);已经使用了路径的/hook部分,所以在路由器中,您只需要/。
你最初的组合:
app.use("/hook", hookRouter);
router.get("/hook", ...);将响应URL /hook/hook。
https://stackoverflow.com/questions/74174823
复制相似问题