Python，Regex:不能从方程中获得系数

Question

我试图用正则表达式和后来的多重方程从这个方程中求出系数：

2a+3b=c

然而，我得到了这个恼人的错误。我检查了我的密码，一切对我来说都很好。这是一个错误：

AttributeError: 'int' object has no attribute 'group'

这是我的代码：

import re

all_coefficients = []

def equation_solver(*equations):
    for equation in equations:
        sides = equation.split('=')
        coefficients = []
        for side in sides:
            terms = re.split(r"\+", side)
            for term in terms:
                coefficient = re.match(r"\d", term)
                if coefficient == None:
                    coefficient = 1
                coefficients.append(int(coefficient.group(0)))
        all_coefficients.append(coefficients)


equations = []

while True:
    equations.append(input())
    if input() == 's':
        break

equation_solver(*equations)

提前感谢

Answer 1

这会导致错误，因为re.match在术语c中找不到任何系数，所以如果它没有找到任何系数(仔细阅读)，您将系数值指定为1，但现在不能使用group，因为现在系数是整数！！因此，在将其转换为整数之前使用group函数，它将如下所示：

import re

all_coefficients = []

def equation_solver(*equations):
    for equation in equations:
        sides = equation.split('=')
        coefficients = []
        for side in sides:
            terms = re.split(r"\+", side)
            for term in terms:
                coefficient = re.match(r"\d", term)
                if coefficient == None:
                    coefficient = 1
                else:
                    coefficient = coefficient.group(0) # Use group beforehand
                coefficients.append(int(coefficient))
        all_coefficients.append(coefficients)


equations = []

while True:
    equations.append(input())
    if input() == 's':
        break

equation_solver(*equations)

希望这能有所帮助