用字典的形式给学生打分

Question

拉梅什是学校的校长。每年，他都会任命一些老师，根据他们的分数来计算学生的成绩。由于技术在不断发展，拉梅什希望将这一过程数字化。因此，他决定雇佣一个程序员来完成这项任务。

您将得到一个字典，其中键是名称，值是另一个字典，它包含作为键的主题和作为值的标记。编写一个函数convertMarks，该函数以字典为参数，并返回带有分数替换分数的字典。

校长还提供了与分数范围有关的等级。

(注:包括两个端点)

1年级-标记2​3 A- 91-100 4 B- 81 - 90 5 C- 71 - 80 6 D- 61 - 70 7 E+ - 51 - 60 8 E- 41 - 50 9 F-0- 40 10​

示例输入

{‘Lakshman’：{‘数学’：90，‘英语’：75，‘社会科学’：10}

示例输出

{‘Lakshman’：{‘数学’：B，‘英语’：C，‘社会科学’：F}

Answer 1

def converMarks(d):
for students in d.keys():
    for marks in d[students].keys():
        m = d[students][marks]
        if m>=91 and m<=100:
            d[students][marks] = 'A'
        elif m>=81 and m<=90:
            d[students][marks] = 'B'
        elif m>=71 and m<=80:
            d[students][marks] = 'C'
        elif m>=61 and m<=70:
            d[students][marks] = 'D'
        elif m>=51 and m<=60:
            d[students][marks] = 'E+'
        elif m>=41 and m<=50:
            d[students][marks] = 'E'
        elif m>=0 and m<=40:
            d[students][marks] = 'F'
return d


name = input().split()

d = {}
for i in name:
    d[i] = {}
    subjects = input().split()
    marks = input().split()
    for j in range(len(subjects)):
        d[i][subjects[j]] = int(marks[j])

print(converMarks(d))

Answer 2

         def converMarks(d):
for students in d.keys():
    for marks in d[students].keys():
        m = d[students][marks]
        if m>=91 and m<=100:
            d[students][marks] = 'A'
        elif m>=81 and m<=90:
            d[students][marks] = 'B'
        elif m>=71 and m<=80:
            d[students][marks] = 'C'
        elif m>=61 and m<=70:
            d[students][marks] = 'D'
        elif m>=51 and m<=60:
            d[students][marks] = 'E+'
        elif m>=41 and m<=50:
            d[students][marks] = 'E'
        elif m>=0 and m<=40:
            d[students][marks] = 'F'
return d