用重复嵌套标记反序列化XML

Question

反序列化--在多个级别上重复相同标记的请求的结果，我让它正常工作，但是为了做到这一点，我在尝试反序列化XML之前更改它的格式。

我无法编辑XML的源代码以将其更改为只有一个级别的Diary。

是否有一种无需调整响应就可以调整XML属性以处理反序列化的方法？

XML响应

<?xml version="1.0" ?>
<Root>
    <DiaryDetails>
        <Diary>
            <Diary created_user="value1" created_date="value2" long_text="value3" short_text="value4" entry_type="value5" >Value6</Diary>
        </Diary>
        <Diary>
            <Diary created_user="value7" created_date="value8" long_text="value9" short_text="value10" entry_type="value11" >Value12</Diary>
        </Diary>
    </DiaryDetails>
</Root>

类定义

[XmlRoot("DiaryDetails")]
public class Diaries : List<Diary> { }

[XmlRoot("Diary")]
public class Diary
{
    [XmlAttribute("created_user")]
    public string CreatedBy { get; set; }

    [XmlAttribute("created_date")]
    public string CreatedDate { get; set; }
    [XmlAttribute("long_text")]
    public string LongText { get; set; }

    [XmlAttribute("short_text")]
    public string ShortText { get; set; }

    [XmlAttribute("entry_type")]
    public string Type { get; set; }
}

反序列化方法

internal T DeserilaiseObject<T>(string response)
{
    XmlSerializer serializer = new XmlSerializer(typeof(T));
    T DeserilaisedObject;

    using (TextReader reader = new StringReader(response))
    {
        DeserilaisedObject = (T)serializer.Deserialize(reader);
    }
    return DeserilaisedObject;
}

我目前正在用字符串替换来处理这个问题：

response = response.Replace("<Diary><Diary", "<Diary").Replace("</Diary></Diary>", "</Diary>");

Answer 1

尝试以下几个方面：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Serialization;



namespace ConsoleApplication40
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XmlReader reader = XmlReader.Create(FILENAME);
            XmlSerializer serializer = new XmlSerializer(typeof(Root));
            Root root = (Root)serializer.Deserialize(reader);
 
        }
    }
    [XmlRoot("Root")]
    public class Root
    {
        [XmlArray("DiaryDetails")]
        [XmlArrayItem("Diary")]
        public List<DiaryMain> diaries { get; set; }
    }
    public class DiaryMain
    {
        public Diary Diary { get; set; }
    }

    [XmlRoot("Diary")]
    public class Diary
    {
        [XmlAttribute("created_user")]
        public string CreatedBy { get; set; }

        [XmlAttribute("created_date")]
        public string CreatedDate { get; set; }
        [XmlAttribute("long_text")]
        public string LongText { get; set; }

        [XmlAttribute("short_text")]
        public string ShortText { get; set; }

        [XmlAttribute("entry_type")]
        public string Type { get; set; }
    }
}

Answer 2

假设您只对第二个嵌套级别的属性化Diary元素感兴趣，您可以这样做：

// load your xml into a document
var doc = new XmlDocument();
doc.Load("your_xml_file.xml");

// extract the interesting nodes using xpath
var nodes = doc.SelectNodes("//Diary/Diary");

// deserialize the filtered NodeList (yes it's that clunky)
var serializer = new XmlSerializer(typeof(Diary));
var diaries = nodes.Cast<XmlNode>().Select(x => serializer.Deserialize(new XmlNodeReader(x))).Cast<Diary>().ToArray();