如何同时从地形创建多个胶水爬行器

Question

我正在部署来自terraform的爬虫数组，我希望同时部署一个包含2个或更多爬虫的列表。我使用的是foreach，但是对于dynamodb_target，我无法找到如何将它与特定的爬虫相关联，也就是说，爬虫1具有table_name 1作为dynamodb_target an等等。

main.tf

resource "aws_glue_crawler" "example" {
  for_each = var.crawlerList

    database_name = each.value.database_name
    name          = each.value.crawler_name
    role          = each.value.role
    
  dynamodb_target {
    path = var.table_name
  }
}

variables.tf

variable "table_name" {
  type        = string
  description = "The name of the DynamoDB table to crawler."
}



variable "crawlerList" {
  type = map(object({
    database_name = string
    crawler_name  = string
    role          = string
  }))
}

var.tfvars

table_name = "ref_master_files"


crawlerList = {
  fisrt = ({
    database_name = "dm_web"
    crawler_name  = "example_one"
    role          = "xxxx"
  }),
  second = ({
    database_name = "dm_web"
    crawler_name  = "example_two"
    role          = "xxxx"
  }),
  third = ({
    database_name = "dm_web"
    crawler_name  = "example_third"
    role          = "xxxx"
  }),
}

结果

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Answer 1

很难得到你想要达到的目标，所以我有两个选择。

1. ，您希望为每个爬虫分配不同的table_name。然后-为另一个值展开变量：

variable "crawlerList" {
  type = map(object({
    database_name = string
    crawler_name  = string
    role          = string
    table_name    = string
  }))
}

1. 您有一些没有附加的多变量的table_names变量。那么，您需要的是匹配它们。--

可能是这样的：

tables = ["table1", "table2"]
matches = {"table1": "first", "table2":"second"}

然后你会像这样迭代：

resource "aws_glue_crawler" "example" {
  for_each = var.matches

    database_name = var.crawler_list[each.value].database_name
    name          = var.crawler_list[each.value].crawler_name
    role          = var.crawler_list[each.value].role
    
  dynamodb_target {
    path = var.tables[each.key]
  }
}