php中的嵌套json数组(被转换为string)

Question

$arr = array (
  
      array(
          'type' => 'Tea', 'amount' => $expense_tea, 'desp' => $expense_tea_desc
      ),
      array(
          'type' => 'BusFare', 'amount' => $expense_bus, 'desp' => $expense_bus_desc
      ),
      array(
          'type' => 'Food', 'amount' => $expense_food, 'desp' => $expense_food_desc
      )
  );
    $myObj1->expensedetails = json_encode($arr);
$json1 = json_encode($myObj1);

描述

1. I尝试使用php

创建嵌套的json数组。

产出：

{
    "expensedetails": {
         "[{\"type\":\"Tea\",\"amount\":\"0\",\"desp\":\"0\"},{\"type\":\"BusFare\",\"amount\":\"0\",\"desp\":\"0\"},{\"type\":\"Food\",\"amount\":\"0\",\"desp\":\"0\"}]"
      }
}

解释

1. json已转换为字符串

。

预期产出

{
"expensedetails":
        [
    {"type":"Tea","amount":"0","desp":"0"},
    {"type":"BusFare","amount":"0","desp":"0"},
    {"type":"Food","amount":"0","desp":"0"},
    {"type":"SalaryAdvance","amount":"0","desp":"0"},
    {"type":"OT","amount":"0","desp":"0"},
    {"type":"IceFlakes","amount":"0","desp":"0"}
    ]
}

结论

1. 我需要一个类似于上面期望的代码输出
2. 的代码，但是当我尝试执行嵌套的json数组

时。

Answer 1

你的问题是：

$myObj1->expensedetails = json_encode($arr);

它将expensedetails设置为已经编码为JSON的字符串。

如果您希望它是JSON中的嵌套数组，那么它需要是PHP中的嵌套数组，而不是已经编码的字符串。就这么做吧：

$myObj1->expensedetails = $arr;