如何在预选的起始位置启动python plotly.express太阳爆发图？

Question

我的目标是向用户展示我的python图表中的预选。

举个例子，如果我使用以下代码：

import plotly.express as px
from plotly.offline import plot
data = dict(
    character=["Eve", "Cain", "Seth", "Enos", "Noam", "Abel", "Awan", "Enoch", "Azura"],
    parent=["", "Eve", "Eve", "Seth", "Seth", "Eve", "Eve", "Awan", "Eve" ],
    value=[10, 14, 12, 10, 2, 6, 6, 4, 4])

fig = px.sunburst(
    data,
    names='character',
    parents='parent',
    values='value'
)
plot(fig)

当我运行这段代码时，太阳暴晒会以夏娃为根目录而打开。我想从已经被选中的"Seth“开始。我该怎么做？

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Answer 1

我认为您可以通过level属性在go.Sunburst中而不是在px.sunburst中实现这一点，您可以设置预选哪个级别。现在，如果您单击预选图的中心，它将带您到原始图。

import plotly.graph_objects as go


data = dict(
    character=["Eve", "Cain", "Seth", "Enos", "Noam", "Abel", "Awan", "Enoch", "Azura"],
    parent=["", "Eve", "Eve", "Seth", "Seth", "Eve", "Eve", "Awan", "Eve" ],
    value=[10, 14, 12, 10, 2, 6, 6, 4, 4])

fig = go.Figure(go.Sunburst(
    labels=data['character'],
    parents=data['parent'],
    values=data['value'],
    level = 'Seth'
))
fig.show()

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