替换每秒钟出现的子字符串，Java

Question

试图替换给定字符串“文本”中的“面向对象编程”子字符串的每一秒。我是Java的初学者，任务的目标是只使用String类方法。下面是我到目前为止想出的。预先谢谢你的帮助)

public class ExerciseString {
    public static void main(String[] args) {
        String s = "Object-oriented programming is a programming language model organized around objects rather than \"actions\" and data rather than logic. Object-oriented programming blabla. Object-oriented programming bla.";
        changeToOOP(s);
    }

    static void changeToOOP (String text) {
        String str = "Object-oriented programming"; // добавить игнорирование регистра
        String str2 = "OOP";

        int index = 0;
        int count = 0;

        while (true) {
            index = text.indexOf(str, index);

            if (index != -1) {
                count++;
                index += str.length();

                if (count % 2 == 0){
                    text = text.replace(text.substring(index - str.length(), index), str2);
                }

            }  else {
                break;
            }
        }

        System.out.println(text);
    }
}

Answer 1

String::replace替换了所有的事件，因此它在您的需求中的使用是不正确的。您可以使用

text = text.substring(0, index) + str2 + text.substring(index + str.length());

请注意，0 % 2==0；因此，如果您想替换发生号第二、第四、第六等等，请在内部if块中使用count % 2 != 0。另外，在处理之前的index和count值之后，增加index和count，即在内部if块之后移动以下内容：

count++;
index += str.length();

Demo

public class ExerciseString {
    public static void main(String[] args) {
        String s = "Object-oriented programming is a programming language model organized around objects rather than \"actions\" and data rather than logic. Object-oriented programming blabla. Object-oriented programming bla.";
        changeToOOP(s);
    }

    static void changeToOOP(String text) {
        String str = "Object-oriented programming"; // добавить игнорирование регистра
        String str2 = "OOP";

        int index = 0;
        int count = 0;

        while (true) {
            index = text.indexOf(str, index);
            if (index != -1) {
                if (count % 2 != 0) {
                    text = text.substring(0, index) + str2 + text.substring(index + str.length());
                }
                count++;
                index += str.length();
            } else {
                break;
            }
        }

        System.out.println(text);
    }
}

输出

面向对象编程是一种基于对象而不是“动作”和数据而不是逻辑的编程语言模型。噢，布拉贝拉。面向对象编程bla.