yq -用父节点键分配节点值

Question

我有这个YAML文件：

developers:
  bob:
    softwares:
      - yq:
          version: "1.2.3"
      - visual-studio-code:
          version: "1.2.3"
  john:
    softwares:
      - xcode:
          version: "1.2.3"
      - jq:
          version: "1.2.3"

我试图用yq来修改它，以得到这样的结果：

developers:
  bob:
    softwares:
      - yq:
          version: "1.2.3"
          license-owner: bob
      - visual-studio-code:
          version: "1.2.3"
          license-owner: bob
  john:
    softwares:
      - xcode:
          version: "1.2.3"
          license-owner: john
      - jq:
          version: "1.2.3"
          license-owner: john

请注意，我想使用第二级键作为license-owner的值。

通过使用下面的公式，我得到了一个类似于我想要的结果，但是上下文已经被更改，并且只返回更新的段。

yq '.developers.* | .softwares[].*.license-owner = (. | key)' test.yml

生产：

softwares:
  - yq:
      version: "1.2.3"
      license-owner: bob
  - visual-studio-code:
      version: "1.2.3"
      license-owner: bob
softwares:
  - xcode:
      version: "1.2.3"
      license-owner: john
  - jq:
      version: "1.2.3"
      license-owner: john

知道怎么得到预期的结果吗？

Answer 1

使用|=进行更新，同时保持上下文：

yq '.developers[] |= .softwares[][].license-owner = key' test.yaml

developers:
  bob:
    softwares:
      - yq:
          version: "1.2.3"
          license-owner: bob
      - visual-studio-code:
          version: "1.2.3"
          license-owner: bob
  john:
    softwares:
      - xcode:
          version: "1.2.3"
          license-owner: john
      - jq:
          version: "1.2.3"
          license-owner: john

用mikefarah/yq版本4.27.2测试

另一个更易读的选择是使用with_entries，然后使用mikefarah/yq和kislyuk/yq (注意，后者还需要引用license-owner，因为它包含“特殊字符”)：

.developers |= with_entries(.value.softwares[][]."license-owner" = .key)