如何合并用户项并显示在他的个人资料上？

Question

我所拥有的：

{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-2", "slug": {"_type": "slug", "current": "author-2-slug"}}
{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-3", "slug": {"_type": "slug", "current": "author-3-slug"}}

我想要的：

{"name": "author-2", "slug": {"_type": "slug", "current": "author-2-slug"}}
{"name": "author-1", "slug": {"_type": "slug", "current": "author-1-slug"}}
{"name": "author-3", "slug": {"_type": "slug", "current": "author-3-slug"}}

我试过的是：

const filtered = _.uniqBy(authors, 'slug')

//result [], [], [], []

有解决办法吗？

Answer 1

如果这是存放函数，您应该尝试这样做，如果您不想有两个相同的作者：

const filtered = _.uniqBy(authors, 'name')

Answer 2

const uniqueTags = [];
authors.map((item) => {
  var findItem = uniqueTags.find((x) => x.name === item.name);
  if (!findItem) uniqueTags.push(item);
});