函数执行f-string

Question

我有一个

string = 'long company name with technologies in it'

并希望替换所有以

search_string ='techno'

带着新的记号

replace_string = 'tech'.

我写了一个函数：

def group_tokens(company_name, string_search, string_replace):   
try:
    x = company_name.split(" ") 
    print(f"x = [re.sub('^{string_search}.*', '{string_replace}', i) for i in x]")
    exec(f"x = [re.sub('^{string_search}.*', '{string_replace}', i) for i in x]")
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return(x)
except:
        return np.nan

如果我单独执行这些行，它就能工作。但是这个函数本身不起作用。

group_tokens('long company name with technologies in it', 'techno', 'tech') = 'long company name with technologies in it'

我以为

group_tokens('long company name with technologies in it', 'techno', 'tech') = 'long company name with tech in it'

如何在函数中“执行”f-字符串？

Answer 1

你把事情搞得太复杂了。只需重新分配x：

def group_tokens(company_name, string_search, string_replace):   
  try:
    x = company_name.split(" ") 
    x = [re.sub(f'^{string_search}.*', string_replace, i) for i in x])
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return x
  except:
    return np.nan

但是，重写类似于以下内容的函数可能更容易一些：

def group_tokens(company_name, string_search, string_replace):   
  return re.sub(f'\b{string_search}\S*\s*', f'{string_replace} ', company_name, flags=re.UNICODE);

Answer 2

def replace(string,x,y):
    words = string.split(' ')
    string = ''
    while words:
        word = words.pop(0)
        if word.startswith(x):
            word = y
        string+=word+' '
    return string[:-1]

print(replace('long company name with technologies in it', 'techno', 'tech'))

Answer 3

我肯定把事情复杂化了。谢谢:-)

def group_tokens(company_name, string_search, string_replace):   
  try:
    x = company_name.split(" ") 
    x = [re.sub(f'^{string_search}.*', string_replace, i) for i in x])
    x = " ".join(x)
    x = " ".join(re.split("\s+", x, flags=re.UNICODE))
    return x
  except:
   return np.nan