如何以编程方式显示UIMenu？

Question

我已经为一个UILongPressGestureRecognizer分配了两个UIButton对象。

第一个名为longPressGestureRecognizer，具有minimumPressDuration = 0.5

第二个，命名为prolongedPressGestureRecognizer，具有minimumPressDuration = 1.5

self.longPressGestureRecognizer = [UILongPressGestureRecognizer alloc initWithTarget:self action:@selector(longPress:)]；

        self.longPressGestureRecognizer.delegate = self;
        
        self.longPressGestureRecognizer.minimumPressDuration = 0.5;
        
        self.longPressGestureRecognizer.numberOfTouchesRequired = 1;
        
        self.longPressGestureRecognizer.numberOfTapsRequired = 0;
        
        self.longPressGestureRecognizer.allowableMovement = 10.0;
        
        [self.customButton addGestureRecognizer:self.longPressGestureRecognizer];
     
        self.prolongedPressGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(prolongedPress:)];
        
        self.prolongedPressGestureRecognizer.delegate = self;
        
        self.prolongedPressGestureRecognizer.minimumPressDuration = 1.5;
        
        self.prolongedPressGestureRecognizer.numberOfTouchesRequired = 1;
        
        self.prolongedPressGestureRecognizer.numberOfTapsRequired = 0;
        
        self.prolongedPressGestureRecognizer.allowableMovement = 10.0;
        
        [self.customButton addGestureRecognizer:self.prolongedPressGestureRecognizer];

设想方案：

当第一次开火的时候，我想让事情发生。

当第二次触发时，我希望上下文菜单显示。

目前，我没有办法这样做。

解决办法：

1. 是否可以延迟上下文菜单出现所需的时间？我确信有一个长新闻手势识别器内部显示菜单。我可以修改这个手势识别器吗？

2.是否可以以编程方式显示菜单？

        NSMutableArray* actions = [[NSMutableArray alloc] init];

        [actions addObject:[UIAction actionWithTitle:@"Edit"
                                               image:nil
                                          identifier:nil
                                             handler:^(__kindof UIAction* _Nonnull action) {
            
            // ...
        }]];

        UIMenu* menu =
        [UIMenu menuWithTitle:@""
                     children:actions];
        
        self.customButton.menu = menu;

Answer 1

你可能需要这样的东西。self.layoutButton将菜单显示为主要操作。意思是普通的水龙头。不是一个主要的动作是一个很长的敲打。

NSMutableArray<UIAction *> *actions = [NSMutableArray array];
__weak __typeof__(self) blockSelf = self;
for (NSString *type in sortedKeys) {
        ZoneLayout *layout = [LayoutManager layoutByType:type];
        UIAction *action = [UIAction actionWithTitle:layout.title image:nil identifier:type
                                             handler:^(__kindof UIAction * _Nonnull action) {
                __strong __typeof__(blockSelf) strongSelf = blockSelf;
                if (strongSelf) {
                        strongSelf.layoutType = type;
                        [strongSelf setupZoneLayoutMenu];
                }
        }];
        if ([self.layoutType isEqualToString:type])
                action.state = UIMenuElementStateOn;
        else
                action.state = UIMenuElementStateOff;
        [actions addObject:action];
}
ZoneLayout *layout = [LayoutManager layoutByType:self.layoutType];
if (layout != nil)
        [self.layoutButton setTitle:layout.title forState:UIControlStateNormal];
else
        [self.layoutButton setTitle:@"-" forState:UIControlStateNormal];
self.layoutButton.menu = [UIMenu menuWithChildren:actions];
self.layoutButton.showsMenuAsPrimaryAction = YES;