用于循环工作和读取数据，但没有对csv文件进行写入。

Question

运行此代码时，所有操作都正常，但是输出没有写入CSV文件。我的data.txt文件包含一些链接。

import csv
import requests
from recipe_scrapers import scrape_html
from csv import writer

with open('recipe.csv', 'w', encoding='utf8', newline='') as file:
    thewriter = writer(file)
    header = ['Title', 'Ingredients', 'Instructions', 'Nutrition_Facts', 'image', 'links']
    thewriter.writerow(header)

    with open('data.txt', 'r') as inf:
        for line in inf:
            html = requests.get(line).content
            scraper = scrape_html(html=html, org_url=line)
            thewriter.writerow([scraper.title(), scraper.ingredients(), scraper.instructions(), scraper.nutrients(), scraper.image(), scraper.links()])

Answer 1

如果代码的缩进如您所示，您只会将头写入输出文件，循环输入，然后只尝试从最后一个刮板再写一行，但即使是在退出with块时输出文件被关闭之后。

将最后一行缩进与scraper = ...相同的级别，否则不可能正常工作。如下所示：

with open('recipe.csv', 'w', encoding='utf8', newline='') as file:
    thewriter = writer(file)
    ...

    with open('data.txt', 'r') as inf:
        for line in inf:
            html = requests.get(line).content
            scraper = scrape_html(html=html, org_url=line)
            thewriter.writerow([.....])     # <---- proper indent

Answer 2

我会尝试重新安排逻辑，使之更有秩序。在将来调试代码时，这可能会有所帮助。

正如alexis所指出的，您的问题是不适当的缩进，导致了范围问题。我将重温您选择的一些关于Python范围的培训材料。

from csv import writer

import requests
from recipe_scrapers import scrape_html

with open('recipe.csv', 'w', encoding='utf8', newline='') as file:
    thewriter = writer(file)
    thewriter.writerow(['Title', 'Ingredients', 'Instructions', 'Nutrition_Facts', 'image', 'links'])  # Header
    
    with open('data.txt', 'r') as inf:
        for line in inf:
            html = requests.get(line).content
            scraper = scrape_html(html=html, org_url=line)
            
            thewriter.writerow([scraper.title(), scraper.ingredients(), scraper.instructions(), scraper.nutrients(), scraper.image(), scraper.links()])