使用拆分方法或Regex分隔字符串

Question

在我的项目中，我正在网废UFC网站，以收集每个UFC运动员的总胜利、总损失和总平局。

这是我的代码的一部分，因为我希望分别去除总赢家、总损失和总平局：

import re
record = "10-7-3 (W-L-D)" #W = wins, L= Loss, D= Draws
char = "-"
record+="-"
totalwins = ""
totalloss = ""
totaldraws = ""


correctRecord = re.findall('\[[^\]]*\]|\([^\)]*\)|\"[^\"]*\"|\S+',record)[0]

print("The correct record per fighter is:", correctRecord)

totaldash = 0
for i in range(len(correctRecord)):
    if(record[i] == char):
    
        totaldash+=1
   
   
        if totaldash == 1:
            print("The total wins", totalwins)
            totalwins =""
        elif totaldash ==2:
       
            print("The total losses ", totalwins)
       
            totalwins=""
       
        elif totaldash ==3:
       
            print("The total draws ", totalwins)
   
   
    elif (correctRecord[i] !=char):
        totalwins +=correctRecord[i]

结果如下：

   The correct record per fighter is: 10-7-3
   The total wins 10
   The total losses  7

问题是，我无法说出全部的平局。我还尝试使用条带方法，但没有结果：

correctRecord= str(record.split(separator, 1)[0])

Answer 1

尝试：

import re

record = "10-7-3 (W-L-D)"

wins, loss, draw = map(int, re.findall(r"\d+", record))

print(f"{wins=} {loss=} {draw=}")

指纹：

wins=10 loss=7 draw=3

Answer 2

在数据以不同的顺序工作的情况下，会有一些更复杂的事情发生：

import re

record = "10-3-7 (W-D-L)"
values = re.findall(r'\d+|[WDL]', record)
vdict = dict(zip(values[3:], values[:3]))
print(f'wins={vdict["W"]}, losses={vdict["L"]}, draws={vdict["D"]}')

输出：

wins=10, losses=7, draws=3