RapidApi与Swift

Question

我不明白，如何在Swift项目中实现RapidApi，我做错了什么？

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import Foundation
let headers = [
  "x-rapidapi-host": "community-open-weather-map.p.rapidapi.com",
  "x-rapidapi-key": "[your rapidapi key]"
]
let request = NSMutableURLRequest(url: NSURL(string: "https://community-open-weather-map.p.rapidapi.com/weather?q=London%252Cuk")! as URL,
                                        cachePolicy: .useProtocolCachePolicy,
                                    timeoutInterval: 10.0)
request.httpMethod = "GET"
request.allHTTPHeaderFields = headers
let session = URLSession.shared
let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
  if (error != nil) {
    print(error)
  } else {
    let httpResponse = response as? HTTPURLResponse
    print(httpResponse)
  }
})
dataTask.resume()

我要怎么包装这个，这样它才能工作？

Answer 1

你需要用方法封装你的代码块-

func getWeatherData() {


let headers = [
  "x-rapidapi-host": "community-open-weather-map.p.rapidapi.com",
  "x-rapidapi-key": "[your rapidapi key]"
]

let request = NSMutableURLRequest(url: NSURL(string: "https://community-open-weather-map.p.rapidapi.com/weather?q=London%252Cuk")! as URL,
                                        cachePolicy: .useProtocolCachePolicy,
                                    timeoutInterval: 10.0)
request.httpMethod = "GET"
request.allHTTPHeaderFields = headers
let session = URLSession.shared
let dataTask = session.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
  if (error != nil) {
    print(error)
  } else {
    let httpResponse = response as? HTTPURLResponse
    print(httpResponse)
  }
})
dataTask.resume()

}