养老金计算器信用系统(Python3)

Question

最简单地说，养恤金是雇主根据雇员的工作时间向他们支付的金额。

下面的代码是基于输入数据的代码(“年度开始就业”、“月开始”、“日开始”)。

然后，我有一个循环，每一年，并计算你工作的天数，这一年之间的两个日期。

Let us say for this EXAMPLE: 

    -The Date Started: January 2, 2020 
    -The Date Ended:   June 23,2023

    from datetime import timedelta, date

    #For the Input Information  

    #Beginning Dates
    print("===============================START WORK DATE INFO======================================\n")
    YearStartEMP  = int(input("Please Enter The Year Employment Started:"))
    MonthStartEMP = int(input("Please Enter The Month Employment Started:"))
    StartDayEmp   = int(input("Please Enter The Day # Employment Started:"))

    #End of Work dates
    print("===============================END WORK DATE INFO======================================\n")  
    YearEndEMP    = int(input("Please Enter The Year Employment Ended:"))
    MonthEndEMP   = int(input("Please Enter The Month Employment Ended:"))
    EndDayEmp     = int(input("Please Enter The Day#  Employment Ended:"))

    print("===============================DAYS PER YEAR WORKED=======================================\n")
    #dates entered 
    StartWork = date(YearStartEMP, MonthStartEMP, StartDayEmp)
    EndWork = date(YearEndEMP, MonthEndEMP, EndDayEmp) + timedelta(days=1)

    #While loop to look through each year and count the days per year for each year betwwen dates
    while StartWork < EndWork:
        next_year = StartWork.replace(year=StartWork.year + 1, month=1, day=1)
        if next_year < EndWork:
            diff = next_year - StartWork
        else:
            diff = EndWork - StartWork
        print(f'{StartWork.year}: {diff.days} days')
        StartWork = next_year

这就是我给出的信息的输出结果。

    ===============================START WORK DATE INFO=======================================

    Please Enter The Year Employment Started:2020
    Please Enter The Month Employment Started:1
    Please Enter The Day # Employment Started:2
    ===============================END WORK DATE INFO=========================================

    Please Enter The Year Employment Ended:2023
    Please Enter The Month Employment Ended:6
    Please Enter The Day#  Employment Ended:23
    ===============================DAYS PER YEAR WORKED=======================================

    2020: 365 days
    2021: 365 days
    2022: 365 days
    2023: 174 days

我的问题是，对于"===DAYS年WORKED===“下的代码部分，应该使用什么代码或函数来使输出看起来像这样。假设退休人员只需要180天就能获得年度的信用，我应该使用什么样的if语句或函数。应该是这样的。

    2020: 365 days, 1 credit
    2021: 365 days, 1 Credit 
    2022: 365 days, 1 Credit 
    2023: 174 days, 0 Credit 

或者类似的东西：

    2020: 365 days 
    2021: 365 days  
    2022: 365 days  
    2023: 174 days  
    
    2020:  1 credit
    2021:  1 Credit 
    2022:  1 Credit 
    2023:  0 Credit       

我尝试过这样做，但是它导致了一个错误：

    if DateBracket >= 180:
        Credit = 1
        print("1 credit") 
    elif DateBracket < 180:
        Credit = 0
        print("0 credit")

Answer 1

这是你的工作代码。我添加了一些评论来解释我所做的改变：

from datetime import timedelta, date

# For the Input Information  

# Beginning Dates
print("===============================START WORK DATE INFO======================================\n")
# Added the `.strip()` method to remove whitespaces from the input
YearStartEMP  = int(input("Please Enter The Year Employment Started: ").strip())
MonthStartEMP = int(input("Please Enter The Month Employment Started: ").strip())
StartDayEmp   = int(input("Please Enter The Day # Employment Started: ").strip())

# End of Work dates
print("===============================END WORK DATE INFO======================================\n")  
YearEndEMP    = int(input("Please Enter The Year Employment Ended: ").strip())
MonthEndEMP   = int(input("Please Enter The Month Employment Ended: ").strip())
EndDayEmp     = int(input("Please Enter The Day # Employment Ended: ").strip())

print("===============================DAYS PER YEAR WORKED=======================================\n")

# Dates entered 
StartWork = date(YearStartEMP, MonthStartEMP, StartDayEmp)
EndWork = date(YearEndEMP, MonthEndEMP, EndDayEmp) + timedelta(days=1)

# Also keep track of the total number of credits for simplicity
total_credits = 0

# While loop to look through each year and count the days per year for each year betwwen dates
while StartWork < EndWork:

    next_year = StartWork.replace(year=StartWork.year + 1, month=1, day=1)

    if next_year < EndWork:
        # We only need the number of days worked in this year, not the whole timedelta
        days_per_year = (next_year - StartWork).days
    else:
        days_per_year = (EndWork - StartWork).days
    
    # Set `credits` to 1 if the employee worked at least 180 days in the year
    # Else, set `credits` to 0
    credits = 1 if days_per_year >= 180 else 0

    # The code above is equivalent to the following, but it's cleaner
    """
        if days_per_year >= 180:
            credits = 1
        else:
            credits = 0
    """

    # Also print the credits for the year
    print(f'{StartWork.year}: {days_per_year} days, {credits} credit(s)')

    StartWork = next_year
    # Update the total number of credits
    total_credits += credits


print(f'Total credits: {total_credits}')

这是样本输出：

===============================START WORK DATE INFO======================================

Please Enter The Year Employment Started: 2020
Please Enter The Month Employment Started: 1
Please Enter The Day # Employment Started: 2
===============================END WORK DATE INFO======================================

Please Enter The Year Employment Ended: 2023
Please Enter The Month Employment Ended: 6
Please Enter The Day # Employment Ended: 23
===============================DAYS PER YEAR WORKED=======================================

2020: 365 days, 1 credit(s)
2021: 365 days, 1 credit(s)
2022: 365 days, 1 credit(s)
2023: 174 days, 0 credit(s)
Total credits: 3