用列表理解从两个列表之间的子字符串中获取新列表

Question

有以下两个列表

a =["my car","your car","his car","her car","their car","her bike","your house","his job"]
b = ["your","her"]

我试图从list a中获取元素，该元素包含list b中的元素字符串，顺序相同，因此预期的输出如下

out = ["your car","her car","her bike","your house"]

我对嵌套for循环的尝试是这样的

out = []
for z in a:
    for w in b:
        if w in z:
            out.append(z)

我被困在试图转化为清单理解。我已经尝试了this问题的建议，但我得到了错误的答案。谢谢你的帮助

>>> [[z for z in a] for w in z if w in z]
[['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job'], 
 ['my car', 'your car', 'his car', 'her car', 'their car', 'her bike', 'your house', 'his job']]
>>>

Answer 1

[ELEMENT for x in a for y in b if y in x]

元素:在满足尾随条件的情况下，为其右侧的每次迭代定义哪个表达式。

>>> a =["my car","your car","his car","her car","their car","her bike","your house","his job"]
>>> b = ["your","her"]
>>> [x for x in a for y in b if y in x]
['your car', 'her car', 'her bike', 'your house']

Answer 2

考虑到您说的解决方案确实有效：

out = []
for z in a:
    for w in b:
        if w in z:
            out.append(z)

将其转换为列表理解基本上就像读取堆栈。

out = [z for z in a for w in b if w in z]