在python中，如何在段落的句子中设置单词限制？

Question

在列表中追加时需要设置限制。

sent = 'Python is dynamically-typed and garbage-collected. It supports multiple programming paradigms, including structured (particularly procedural), object-oriented and functional programming.'

我只需要在一个句子中设置5个单词并附加到一个列表中。

产出应-

sent_list = ['Python is dynamically-typed and garbage-collected.', 'It supports multiple programming paradigms,', 'including structured (particularly procedural), object-oriented', 'and functional programming.']

Answer 1

试试这个：

words = sent.split(' ')
sent_list = [' '.join(words[n:n+5]) for n in range(0, len(words), 5)]

Answer 2

也许有点不正统：

sent_list = [re.sub(r'\s$','',x.group('pattern')) for x in 
     re.finditer('(?P<pattern>([^\s]+\s){5}|.+$)',sent)]

['Python is dynamically-typed and garbage-collected.',
 'It supports multiple programming paradigms,',
 'including structured (particularly procedural), object-oriented',
 'and functional programming.']

解释'(?P<pattern>([^\s]+\s){5}|.+$)'

• (?P<pattern> ... )：化妆品，创建一个命名捕获group.
• ([^\s]+\s){5}：查找序列的非空白字符(一个或多个)后的空白；然后重复5 times.
• |.+$：，一旦第一个选项已经用完，只需将最后一位一直读到末尾。

我们使用re.finditer循环遍历所有的match objects，并使用x.group('pattern')获取匹配。除了最后一次匹配之外，所有这些都将在最后有一个额外的空格；消除它的一种方法是使用re.sub。

Answer 3

sent = 'Python is dynamically-typed and garbage-collected. It supports multiple programming paradigms, including structured (particularly procedural), object-oriented and functional programming.'
sent_list = ['Python is dynamically-typed and garbage-collected.', 
            'It supports multiple programming paradigms,', 
            'including structured (particularly procedural), object-oriented', 
            'and functional programming.']

new_list = []
inner_string = ""
sentence_list = sent.split(" ")
for idx, item in enumerate(sentence_list):
    if (idx+1)==1 or (idx+1)%5 != 0:
        if (idx+1) == len(sentence_list):
            inner_string += item
            new_list.append(inner_string)
        else:
            inner_string += item + " "
    elif (idx+1)!=1 and (idx+1) % 5 == 0 :
        inner_string += item
        new_list.append(inner_string)
        inner_string = ""
        
print(new_list)
print(new_list == sent_list)

输出：

['Python is dynamically-typed and garbage-collected.', 'It supports multiple programming paradigms,', 'including structured (particularly procedural), object-oriented', 'and functional programming.']
True