POST API问题-不起作用

Question

下午好,

我在api POST请求方面遇到了麻烦--它根本不会出现在API日志上--我有各种get请求运行良好，但这个请求没有--我不知道我做错了什么。

public function broadband_plan(){
        $common = array();
        $common['main_menu'] = 'Broadband plan';

        $cli_or_postcode = isset($_GET["cli_or_postcode"]) ? $_GET["cli_or_postcode"] : "";
        $district_id = isset($_GET["district_id"]) ? $_GET["district_id"] : "";
        $sub_premises = isset($_GET["sub_premises"]) ? $_GET["sub_premises"] : "";
        $premises_name = isset($_GET["premises_name"]) ? $_GET["premises_name"] : "";
        $thoroughfare_number = isset($_GET["thoroughfare_number"]) ? $_GET["thoroughfare_number"] : "";
        $thoroughfare_name = isset($_GET["thoroughfare_name"]) ? $_GET["thoroughfare_name"] : "";
        $locality = isset($_GET["locality"]) ? $_GET["locality"] : "";
        $postcode = isset($_GET["postcode"]) ? $_GET["postcode"] : "";
        $nad_key = isset($_GET["nad_key"]) ? $_GET["nad_key"] : "";
        $post_town = isset($_GET["post_town"]) ? $_GET["post_town"] : "";
        $county = isset($_GET["county"]) ? $_GET["county"] : "";
        $district_id = isset($_GET["district_id"]) ? $_GET["district_id"] : "";

        $request = array();
        $request['apiUsername'] = 'XXXXXXX';
        $request['apiPassword'] = 'XXXXXXX';
        $request['encryption']   = 'SHA-512';
        $request['platform']     = 'LIVE';
        $request['method']       = 'POST';
        
        $address = '{
            "sub_premises": $sub_premises,
            "premises_name": $premises_name,
            "thoroughfare_number": $thoroughfare_number,
            "thoroughfare_name": $thoroughfare_name,
            "post_town": $post_town,
            "postcode": $postcode,
            "district_id": $district_id,
            "nad_key": $nad_key
        }';
        $address = json_encode($address);

        $request['url'] = "/broadband/availability" . $address;
        
        
    
        $broadband_plan_detail = array();
        if (!empty($address)) {
            $broadband_plan_detail = $this->get_plan($request);
        }

        return view('front.broadband_plan',compact('common','broadband_plan_detail'));
    }

Answer 1

$address after $address = json_encode($address)；将是一个对象，它不能作为字符串连接在$request‘’url‘=“/宽频/可用性”中。$address；

请检查您的API并确保您遵循它们的结构，例如，如果API URL接受参数作为GET请求，您可以传递参数如下：

$request‘’url‘=“/宽频/可用性?子房地=”。$sub_premises。"&premises_name=“。$premises_name...

基于您的代码，API方法是POST，因此您可能需要将参数作为数组来准备。