如何在python中使用多重处理来监视机器人手臂的坐标？

Question

在执行x时，我使用下面的代码打印y和Move_Relative()坐标。移动相对函数似乎没有被执行，因为在执行结束时，我的输出是(x = 0和y = 0)。我做错了什么？

import multiprocessing
from multiprocessing import Pool
import sys

x = 0
y = 0


def monitor_coordinates():
    global x
    global y
    print("x: " + str(x) + " y: " + str(y))
    
    
def Move_Relative():    
    global x
    global y
    while x < 100000:
        x = x + 1   
        y = y + 0.5

if __name__=='__main__':
   
    q = multiprocessing.Process(target = Move_Relative) 
    q.start()
    p = multiprocessing.Process(target = monitor_coordinates)    
    p.start()
    
    q.join()
    p.join()

Answer 1

全局变量在进程之间不共享。一个很好的选择是使用multiprocessing.Value

import multiprocessing
from multiprocessing import Pool, Value
import sys

x = Value('d', 0)
y = Value('d', 0)


def monitor_coordinates(x, y):
    print("x: " + str(x.value) + " y: " + str(y.value))


def Move_Relative(x, y):
    while x.value < 100000:
        x.value = x.value + 1
        y.value = y.value + 0.5


if __name__ == '__main__':
    q = multiprocessing.Process(target=Move_Relative, args=(x, y))
    q.start()
    p = multiprocessing.Process(target=monitor_coordinates, args=(x, y))
    p.start()

    q.join()
    p.join()

产出：

x: 88826.0 y: 44413.0