TypeScript -按键分组对象

Question

我的目标如下：

const original = [{
        "key-8": {
            "some object"
        }
    },
    {
        "key-12": {
            "some object"
        }
    },
    {
        "key-12": {
            "some object"
        }
    },
    {
        "key-1": {
            "some object"
        }
    },
    {
        "key-8": {
            "some object"
        }
    }
]

如您所见，我有两个key-8对象和两个key-12对象。我想将它们结合起来(顺序并不重要)，因此输出如下：

{
    {
        "key-12": [{
                "some object"
            },
            {
                "some object"
            }
        ]
    }, {
        "key-1": {
            {
                "some object"
            }
        },
        {
            "key-8": [{
                    "some object"
                },
                {
                    "some object"
                }
            ]
        }
    }
}

不管我做什么，我都不能让它起作用。我使用了reduce，我使用了常规的forEach和其他简单的“黑客”，因为TypeScript不喜欢它们。

有人能帮忙吗？

Answer 1

尝尝这个

​

const orig = [
  {
    "key-8": {
      "key": "...",
      "value": "...",
      "info": "..."
    }
  },
  {
    "key-12": {
      "key": "...",
      "value": "...",
      "info": "..."
    }
  },
  {
    "key-12": {
      "key": "...",
      "value": "...",
      "info": "..."
    }
  },
  {
    "key-1": {
      "key": "...",
      "value": "...",
      "info": "..."
    }
  },
  {
    "key-8": {
      "key": "...",
      "value": "...",
      "info": "..."
    }
  }
];


const result = orig.reduce(function (r, a) {
    const { key, ...others } = Object.values(a)[0];
    r[Object.keys(a)] = r[Object.keys(a)] || [];
    r[Object.keys(a)].push(others);
    return r;
  }, Object.create(null));

  console.log(result);

​