如何使用python列表创建单词组合

Question

我有python列表，希望创建一个没有重复的单词组合，并搜索字符串中可用的每个组合。

fruits = ['apple','banana','grape','papaya']

创建上述列表的组合如下：

combination = [" apple banana","apple grape","apple papaya","banana grape","banana papaya", "grape papaya"]

是否有可能反转组合列表，例如：

reverse_combination = [" banana apple", "grape apple","papaya apple", "grape banana", "papaya banana", "papaya grape"]

我试着用两个for循环，但我无法得到我需要的东西。如果有人提出更好的逻辑，它将帮助我。谢谢。

Answer 1

使用itertools.combinations

Ex:

import itertools

fruits = ['apple','banana','grape','papaya']

result = []
resultRev = []
for i, v in itertools.combinations(fruits, 2):
    result.append(" ".join([i, v]))
    resultRev.append(" ".join([v, i]))
    
print(result)
print(resultRev)

输出：

['apple banana', 'apple grape', 'apple papaya', 'banana grape', 'banana papaya', 'grape papaya'] 
['banana apple', 'grape apple', 'papaya apple', 'grape banana', 'papaya banana', 'papaya grape']

Answer 2

可以使用两个for-循环.

for fruit_idx1 in range(0, len(fruits) - 1):
    for fruit_idx2 in range(fruit_idx1 + 1, len(fruits) - 1):
        combination.append(f"{fruits[fruit_idx1]} {fruits[fruit_idx2]}")

您可以通过这样做来逆转它：

for combo in combination:
    reverse_combination.append(' '.join(combo.split()[::-1]))