从字典列表创建字典

Question

我想从字典列表中创建一本新字典。

要求的产出是，请建议：

data2 = {'NUM': [ID], 'NUM': [ID]}
data2 = {'13': [16,4], '131': [12, 11], '132': [9,8]}

我尝试了Python代码如下：

data = [{'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-13/ID-16'},
{'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-131/ID-12'}, 
{'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-132/ID-9'}, 
{'object':'XXXX-TSS/RDID-1579/NBLO-723/NUM-13/ID-4'}, 
{'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-131/ID-11'}, 
{'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-132/ID-8'}]
data2 = {}
for row in data:
    obj = row['object']
    num = obj.split('/')[3].split('-')[-1]
    _id = int(obj.split('-')[-1])
    if num not in data2:
        data2[data2] = _id

这给我的结果是：{'13': 16, '131': 12, '132': 9}

Answer 1

您可以使用一个简单的regexp来获得请求的输出：

data = [
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-13/ID-16'},
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-131/ID-12'},
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-132/ID-9'},
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-13/ID-4'},
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-131/ID-11'},
    {'object': 'XXXX-TSS/RDID-1579/NBLO-723/NUM-132/ID-8'}
]

result = {}
pattern = re.compile(r'NUM-(\d+)/ID-(\d+)')
for adict in data:
    num, id = re.findall(pattern, adict['object'])[0]
    result.setdefault(num, []).append(int(id))

print(result)

输出：

{'13': [16, 4], '131': [12, 11], '132': [9, 8]}