如何提取普通的“to”以保持脚本的干燥？

Question

我有以下内容(从https://stackoverflow.com/a/70152440/807037修改)：

yq eval-all '
    .clusters = ( 
        (   
            (.clusters[] | {.name: .}) as $item ireduce ({}; . * $item)
        ) as $uniqueMap |
        ( $uniqueMap  | to_entries | .[]) as $item ireduce([]; . + $item.value)
    ) | 
    .contexts = ( 
        (
            (.contexts[] | {.name: .}) as $item ireduce ({}; . * $item)
        ) as $uniqueMap |
        ( $uniqueMap  | to_entries | .[]) as $item ireduce([]; . + $item.value)
    ) | 
    select(fi == 0)' konfig monfig

如何提取以下通用代码以使脚本保持干燥：

.«KEY» = (
        (
            (.«KEY»[] | {.name: .}) as $item ireduce ({}; . * $item)
        ) as $uniqueMap |
        ( $uniqueMap  | to_entries | .[]) as $item ireduce([]; . + $item.value)
    )

输入文件：

# konfig
apiVersion: apiVersion-keep
clusters:
- cluster:
    certificate-authority-data: cad-0
    server: server-0
  name: name-0
- cluster:
    certificate-authority-data: cad-1-discard
    server: server-1-discard
  name: name-1
- cluster:
    certificate-authority-data: cad-2
    server: server-2
  name: name-2
contexts:
- context:
    cluster: cluster-0
    user: user-0
  name: name-0
- context:
    cluster: cluster-1-discard
    user: user-1-discard
  name: name-1
- context:
    cluster: cluster-2
    user: user-2
  name: name-2
current-context: name-keep

# monfig
apiVersion: apiVersion-discard
clusters:
- cluster:
    certificate-authority-data: cad-1-keep
    server: server-1-keep
  name: name-1
contexts:
- context:
    cluster: cluster-1-keep
    user: user-1-keep
  name: name-1
current-context: name-discard

预期：

apiVersion: apiVersion-keep
clusters:
- cluster:
    certificate-authority-data: cad-0
    server: server-0
  name: name-0
- cluster:
    certificate-authority-data: cad-1-keep
    server: server-1-keep
  name: name-1
- cluster:
    certificate-authority-data: cad-2
    server: server-2
  name: name-2
contexts:
- context:
    cluster: cluster-0
    user: user-0
  name: name-0
- context:
    cluster: cluster-1-keep
    user: user-1-keep
  name: name-1
- context:
    cluster: cluster-2
    user: user-2
  name: name-2
current-context: name-keep

Answer 1

这个问题比看起来要复杂一些，因为|=的一个用例正在更新每个匹配的左侧节点。.clusters会产生两个节点(与.contexts一样)，每个节点都会被独立更新。yq不知道如何将节点分组。在玩了一会儿之后，我把这个做好了：

./yq eval-all '
  . ref $r |
  with( ("clusters", "contexts"); 
    $r[.] = ( 
        (
            ($r[.] | .[] | {.name: .}) as $item ireduce ({}; . * $item)
        ) as $uniqueMap |
        ( $uniqueMap  | to_entries | .[]) as $item ireduce([]; . + $item.value)
    )
  ) | select(fi==0)' file1.yaml file2.yaml

解释：

• . ref $r创建对根上下文的引用，称为$r。这与顶级节点(file1和file2)匹配。
• 使用with运算符，我可以根据$r参数化合并表达式，传入需要合并的两条路径。每个路径都是针对$r[.]中的根上下文$r[.]运行的。

希望这是合理的！

免责声明:我写了yq

Answer 2

一般来说(由于缺少样本数据)，您可以使用更新操作符 |= (从v4.3.0开始就可以使用)，使您能够在RHS上通过上下文.来解决问题。然后，由于绝对上下文只出现在LHS上，您可以立即列出所有您希望将其应用到的上下文。

(.clusters, .contexts) |= ( .[] | ... )