如何在Javascript中循环另一个数组中的数组？

Question

考虑到这个脚本

<script>
var sentences= 
[
 ['journey27.mp4', 
  [
    [1, 2],
    [5, 7]
  ]
 ],
 ['journey28.mp4', 
  [
    [10, 12],
    [13, 17],
    [25, 36]
  ]
 ],
 ['journey30.mp4', 
  [
    [13, 15],
    [15, 19]
  ]
 ]
];

function playVideo(myUrl, startTime, endTime) { 
  console.log(`Playing ${myUrl} from ${startTime} to ${endTime}`);
} 
function myLoop(){
//what should I fill in here?
}
</script>

我想打印这个结果：

从1到2播放‘游历27.mp4’

从1到2播放‘游历27.mp4’

从1到2播放‘游历27.mp4’

从5点到7点演奏“旅程27.mp4”

从5点到7点演奏“旅程27.mp4”

从5点到7点演奏“旅程27.mp4”

从10点到12点演奏“旅程28 mp4”

从10点到12点演奏“旅程28 mp4”

从10点到12点演奏“旅程28 mp4”

从13到17演奏“旅程28 mp4”

从13到17演奏“旅程28 mp4”

从13到17演奏“旅程28 mp4”

25至36岁演奏“旅程28 mp4”

25至36岁演奏“旅程28 mp4”

25至36岁演奏“旅程28 mp4”

从13到15演奏“旅程30.mp4”

从13到15演奏“旅程30.mp4”

从13到15演奏“旅程30.mp4”

从15到19演奏“旅程30.mp4”

从15到19演奏“旅程30.mp4”

从15到19演奏“旅程30.mp4”

注意事项：子数组的每一行应该播放3次，然后移动到下一行。

myLoop 如何填写函数输出上述结果？

Answer 1

您可以尝试这种方法。

​

var data = [
  ['journey27.mp4',
    [
      [1, 2],
      [5, 7]
    ]
  ],
  ['journey28.mp4',
    [
      [10, 12],
      [13, 17],
      [25, 36]
    ]
  ],
  ['journey30.mp4',
    [
      [13, 15],
      [15, 19]
    ]
  ]
];

function playVideo(myUrl, startTime, endTime) {
  console.log(`Playing ${myUrl} from ${startTime} to ${endTime}`);
}

function myLoop(sentences, lineCount) {
  for (const sentence of sentences) {
    const [video, timers] = sentence //extract video url and the timer array
    for (const timer of timers) {
      const [startTime, endTime] = timer //extract start time and end time in each timer
      for (let i = 0; i < lineCount; i++) {
        playVideo(video, startTime, endTime) //console.log for each line
      }
    }
  }
}

const lineCount = 3 //will print 3 times
myLoop(data, lineCount)

​