Python2D列表问题

Question

现在我有一个这样的清单：

list1 = [
[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 1, 2, 3],
[4, 5, 6, None]
]

然后定义一个函数：

def thefunction(position: tuple[int, int], board: Board) -> bool:

现在我希望这个函数返回一个bool值，如果给定的(行，列)位置为"None"，返回True，否则，返回False

thefunction((0,0), list1)
False

thefunction((3,3), list1)
True

遇到的问题是，我不知道如何对列表的(行、列)信息进行比较，然后输出bool值。

Answer 1

尝试使用tuple[int, ...]作为您的位置提示类型：

from typing import Optional


def is_none(position: tuple[int, ...], board: list[list[Optional[int]]]) -> bool:
    if not len(board) or not all(len(row) == len(board) for row in board):
        raise ValueError('Invalid board, must be square.')
    board_rows, board_cols = len(board), len(board[0])
    if len(position) != 2:
        raise ValueError('Position must have exactly two values.')
    row, col = position
    if 0 <= row < board_rows and 0 <= col < board_cols:
        return board[row][col] is None
    raise ValueError('Position must be on board.')


def main() -> None:
    board = [
        [1, 2, 3, 4],
        [5, 6, 7, 8],
        [9, 1, 2, 3],
        [4, 5, 6, None],
    ]
    print(is_none((0, 0), board))
    print(is_none((3, 3), board))


if __name__ == '__main__':
    main()

输出：

False
True