scala中使用circe的json解析

Question

我试图利用circe在scala中进行json解析。你能帮我解析一下案例类中的数据吗？以下是代码：

import io.circe.Decoder
import io.circe.generic.semiauto.deriveDecoder
import io.circe.parser

val json: String =
"""
{
    "segmements": [
        {
            "tableName": "X",
            "segmentName": "XX",
            "pocs": [
                "aa@aa.com",
                "bb@bb.com"
            ]
        },
        {
            "tableName": "Y",
            "segmentName": "YY",
            "pocs": [
                "aa@aa.com",
                "bb@bb.com"
            ]
        }
    ]
}
"""

final case class TableInfo(tableName: String, segmentName: String)
object TableInfo {
  implicit final val TableInfoDecoder: Decoder[TableInfo] = deriveDecoder
}

val result = for {
  data <- parser.parse(json)
  obj <- data.asObject.toRight(left = new Exception("Data was not an object"))
  segmements <- obj("segmements").toRight(left = new Exception("Json didn't had the 
segments key"))
  r <- segmements.as[List[TableInfo]]
} yield r

println(result)

链接：https://scastie.scala-lang.org/BalmungSan/eVEvBulOQwGzg5hIJroAoQ/3

Answer 1

只需添加作为String集合类型的参数

final case class TableInfo(tableName: String, segmentName: String, pocs: Seq[String])

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