如何修改Arduino灌溉项目的代码，使其不会在1次演示后终止

Question

我使用的是一个arduino uno，一个土壤水分传感器和一个微型水泵，当传感器检测到水分不足时，微型水泵被激活并泵水，直到传感器记录到水分增加(例如在土壤中)，这就是它应该如何工作的方式，但是当我从潮湿的土壤水中取出传感器时，我必须再次开始运行代码，这就是我需要帮助的地方，我不希望它终止，需要修改的代码如下

int relayPin = 8;
int sensor_pin = A0; // Soil Sensor input at Analog PIN A0
int output_value ;
void setup()         // put your setup code here, to run once:
{ 
  Serial.begin(9600);                 
  pinMode(relayPin, OUTPUT);
  pinMode(sensor_pin, INPUT);
  Serial.println("Reading From the Sensor ...");
  delay(2000);
}

void loop()
{
 output_value= analogRead(sensor_pin);
 output_value = map(output_value,550,10,0,100);
 Serial.print("Mositure : ");
 Serial.print(output_value);
 Serial.println("%");
 if(output_value<20){
  digitalWrite(relayPin, LOW);
 }
 else
 {
  digitalWrite(relayPin, HIGH);       
 }
 delay(1000);
}

Answer 1

在将土壤传感器从地面移除后，当AN0模拟输入产生小于连续条件(< 20)的值时，继电器不会工作。

enum runMode {
  DEBUG,  // When the ground sensor isn't in the ground
  RELEASE // When the ground sensor is in the ground
};

int relayPin = 8;
int sensor_pin = A0;
int output_value;

/* Debug mode has been activated. */
enum runMode mode = DEBUG;

void setup() { 
  Serial.begin(9600);                 
  pinMode(relayPin, OUTPUT);
  pinMode(sensor_pin, INPUT);
  Serial.println("Reading From the Sensor ...");
  delay(2000);
}

void loop() {  
  output_value= analogRead(sensor_pin);
  output_value = map(output_value,550,10,0,100);
  Serial.println("Mositure: " + String(output_value) + "%");

  if(mode == DEBUG)
    debugMode();
  else
    releaseMode();

  delay(1000);
}

// When debug mode is active, the relay changes position at 1 second intervals
void debugMode() {
  if(digitalRead(relayPin) == HIGH) {
    digitalWrite(relayPin, LOW);  
  }
  else {
    digitalWrite(relayPin, HIGH);
  }
}

// When the release mode is active, the soil sensor must be in the ground.
void releaseMode() {
  if(output_value < 20) {
    digitalWrite(relayPin, LOW);
  }
  else {
    digitalWrite(relayPin, HIGH);       
  }
}