当我试图渲染标签时，我得到了Wallpaper.Wallpaper.None

Question

views.py

def download(request, wallpaper_name):
try:
    wallpaper = Wallpaper.objects.get(name=wallpaper_name)
    similar_wallpapers = wallpaper.tags.similar_objects()[:2]

except Exception as exc:
    wallpaper = None
    similar_wallpapers = None
    messages.error = (request, 'Sorry! data does not exist')

context = {'wallpaper': wallpaper, 'similar_wallpapers': similar_wallpapers}
return render(request, 'Wallpaper/download.html', context)

models.py

class Tags(models.Model):
tag = models.CharField(max_length=100)

def __str__(self):
    return self.tag



class Wallpaper(models.Model):
    name = models.CharField(max_length=100, null=True)
    size = models.CharField(max_length=50, null=True)
    pub_date = models.DateField('date published', null=True)
    resolution = models.CharField(max_length=100, null=True)
    category = models.ManyToManyField(Category)
    tags = TaggableManager()
    Device_Choices = [
        ('PC', 'pc'),
        ('mobile', 'mobile')
    ]
    Devices = models.CharField(max_length=20,choices=Device_Choices, default= 'PC')
    image = models.ImageField(upload_to='Wallpaper/Images/', default="")

    def __str__(self):
        return self.name

download.html

​

<div class="tag">
    <h3>Tags</h3>
    <ul>

        <li>{{wallpaper.tags}}</li>

    </ul>
    
</div>

​

我要把那个墙纸的所有标签都渲染出来。

如果可能的话，请告诉我是否有其他方法来处理标签，因为使用taggit非常困难，我得到了manny错误。

Answer 1

标记是一个多到多的关系，因此您需要在模板中使用.all来获得它们。但是，这只会向您展示查询集，因此您需要遍历它们以呈现它们的名称：

<ul>
{% for tag in wallpaper.tags.all %}
    <li>{{ tag.name }}</li>
{% endfor %}
</ul>