“交互”对象没有属性'bot‘nextcord菜单

Question

我使用https://replit.com/为朋友构建一个不和谐的机器人，在我运行命令之前一切都很顺利，它给了我这个错误，我知道这意味着什么或者如何修复它，有人能帮忙吗？

错误：

Ignoring exception in command <nextcord.application_command.SlashApplicationCommand object at 0x7f4bc8784df0>:
Traceback (most recent call last):
  File "/home/runner/nextcord/venv/lib/python3.8/site-packages/nextcord/application_command.py", line 824, in invoke_callback_with_hooks
    await self(interaction, *args, **kwargs)
  File "main.py", line 37, in delete_things
    confirm = await Confirm('Delete everything?').prompt(ctx)
  File "main.py", line 26, in prompt
    await self.start(ctx, wait=True)
  File "/home/runner/nextcord/venv/lib/python3.8/site-packages/nextcord/ext/menus/menus.py", line 684, in start
    self.bot = ctx.bot
AttributeError: 'Interaction' object has no attribute 'bot'

The above exception was the direct cause of the following exception:

nextcord.errors.ApplicationInvokeError: Command raised an exception: AttributeError: 'Interaction' object has no attribute 'bot'

您可以在这里看到代码，https://replit.com/join/qcbhddmqnn-hamishmcd

Answer 1

您需要将交互传递给交互kwarg。

斜杠命令为您提供一个名为Interaction的类型，而不是Context，因此不应该将其称为ctx。

参见本例：https://menus.docs.nextcord.dev/en/stable/ext/menus/menu_examples/#slash-commands

@bot.slash_command()
async def slash_menu(interaction: nextcord.Interaction):
    await MySlashButtonMenu().start(interaction=interaction)

注意，在开始时，斜杠命令交互作为关键字参数传递给函数。

在您的示例中，您需要提示符来进行交互，并使用self.interaction来发送消息，而不是使用ctx或通道。

async def send_initial_message(self, ctx, channel):
    await self.interaction.response.send_message(self.msg, view=self)
    return await self.interaction.original_message()

...

async def prompt(self, interaction):
    await self.start(interaction=interaction, wait=True)
    return self.result

...

@bot.slash_command()
async def delete_things(interaction):
    confirm = await Confirm('Delete everything?').prompt(interaction)
    if confirm:
        await interaction.send('deleted...')

我建议阅读上面链接的文档来理解差异。