我在我的项目中使用了react路由器-dom v6和mobex,当我使用它时会得到一个错误,如下所示。
main.tsx:
import React from 'react'
import ReactDOM from 'react-dom/client'
import App from './app/layout/App'
import './app/layout/styles.css'
import 'semantic-ui-css/semantic.min.css'
import 'react-toastify/dist/ReactToastify.min.css'
import 'react-calendar/dist/Calendar.css'
import 'react-datepicker/dist/react-datepicker.css'
import { store, StoreContext } from './app/stores/store'
import { BrowserRouter } from 'react-router-dom'
import { useNavigate } from 'react-router-dom';
export const navigate = useNavigate();
ReactDOM.createRoot(document.getElementById('root')!).render(
<React.StrictMode>
<StoreContext.Provider value={store}>
<BrowserRouter>
<App />
</BrowserRouter>
</StoreContext.Provider>
</React.StrictMode>
)userStore.ts:
import { UserFormValues } from './../models/user';
import { makeAutoObservable, runInAction } from "mobx";
import { User } from "../models/user";
import agent from '../api/agent';
import { store } from './store';
import { navigate } from '../../main';
export default class UserStore {
user:User | null = null;
constructor() {
makeAutoObservable(this);
}
logout = () => {
store.commonStore.setToken(null);
window.localStorage.removeItem('jwt');
this.user = null;
navigate('/');
}
}错误:
"Invalid hook call. Hooks can only be called inside the body of a function component"在旧版本中,当我这样做时,它正在工作:
main.tsx:
...
...
import { createBrowserHistory } from "history";
export const history = createBrowserHistory();
...
...和userStore.tsx:
import { makeAutoObservable, runInAction } from "mobx";
import agent from "../api/agent";
import { User, UserFormValues } from "../models/user";
import { store } from "./store";
import { history } from "../../index";
export default class UserStore {
user: User | null = null;
constructor() {
makeAutoObservable(this);
}
logout = () => {
store.commonStore.setToken(null);
window.localStorage.removeItem("jwt");
this.user = null;
history.push("/");
};我该如何解决这个问题?
发布于 2022-07-30 10:53:27
这一行const navigate = useNavigate()只能在一个React组件或自定义钩子中,因为useNavigate是一个钩子。见钩子规则了解更多。解决这一问题的一种方法是更改logout函数,以便将navigate作为参数,如下所示:
logout = (navigate) => {
store.commonStore.setToken(null);
window.localStorage.removeItem("jwt");
this.user = null;
navigate("/");
};并在组件中调用useNavigate,调用logout并将navigate作为参数提供给它。就像这样,例如:
import UserStore from "./UserStore"; // use the correct path
import { useNavigate } from "react-router-dom";
export default function Component() {
const navigate = useNavigate();
const userStore = UserStore();
userStore.logout(navigate);
return <div></div>;
}发布于 2022-07-30 21:33:56
问题
React钩子只能在React函数组件中使用,而useNavigate钩子只能在路由上下文中使用。
解决方案
通过React函数组件通过navigate钩子访问useNavigate函数,并将对navigate的引用传递给logout处理程序。
logout = ({ navigate }) => {
store.commonStore.setToken(null);
window.localStorage.removeItem("jwt");
this.user = null;
navigate("/");
};..。
const SomeComponent = () => {
const navigate = useNavigate();
...
UserStore.logout({ navigate });
...
};替代解
导入和使用HistoryRouter,并像以前一样继续使用自定义history对象。这需要history@5包依赖关系,必要时安装它(运行npm i -S history@5)。
示例:
创建并导出history对象。
import { createBrowserHistory } from "history";
export const history = createBrowserHistory();..。
...
import { unstable_HistoryRouter as HistoryRouter } from 'react-router-dom';
import { history } from '../path/to/history';
ReactDOM.createRoot(document.getElementById('root')!).render(
<React.StrictMode>
<StoreContext.Provider value={store}>
<HistoryRouter history={history}>
<App />
</HistoryRouter>
</StoreContext.Provider>
</React.StrictMode>
);UserStore继续导入并使用history对象。
import { makeAutoObservable, runInAction } from "mobx";
import agent from "../api/agent";
import { User, UserFormValues } from "../models/user";
import { store } from "./store";
import { history } from "../path/to/history";
export default class UserStore {
user: User | null = null;
constructor() {
makeAutoObservable(this);
}
logout = () => {
store.commonStore.setToken(null);
window.localStorage.removeItem("jwt");
this.user = null;
history.push("/");
};
...发布于 2022-07-30 10:35:48
不能在类组件中使用钩子。对于路由槽类组件,还有另一种方法。但我认为在路由器6类组件支持被取消。因此,您可以将类组件更改为函数组件--这是一种简单的方法。
https://stackoverflow.com/questions/73174746
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