如何组合和嵌套相关的JSON对象？

Question

我有两个json文件，我想把它们合并成一个json对象，可以在前端读取。

fragments.json

[
    {
      "id": 2,
      "title": "John Smith is nice",
      "reports": "1,2",
      "entities": 1,
    }
]

entities.json

[
    {
      "id": 1,
      "fragments": 2,
      "name": "John SMITH",
      "dateOfBirth": "4/24/1967",
    }
]

理想的Result.json

我想展示连接到任何给定片段的所有实体。

[
    {
       "id":2,
       "title":"John Smith is nice",
       "reports":"1,2",
       "entities":{
          "id":1,
          "fragments":2,
          "name":"John SMITH",
          "dateOfBirth":"4/24/1967"
       }
    }
 ]

到目前为止，这是我的代码：

router.get('/sprint-3/:prototype/report/:reportId', function (req, res) {

    const slug = +req.params.reportId
    const report = reports.find(({ id }) => id === slug);

    const reportFragments = fragments.filter(({ reports }) => reports.includes(report.id) );

    reportFragments.forEach(fragment => {
        const reportEntities = entities.filter(({ fragments }) => fragments === fragment.id );
        reportFragments.push(reportEntities);
        console.log('New', reportFragments)
    });


    res.render("sprint-3/prototype-1/report", { report: report, fragments: reportFragments });
});

我一直认为.push是这样做的一种方式，但目前它将实体附加到reportFragments的末尾，而不是在每个实体中嵌套。

Answer 1

您可以像这样使用减缩。

​

const reportFragments = [{
  "id": 2,
  "title": "John Smith is nice",
  "reports": "1,2",
  "entities": 1,
}]

const entities = [{
  "id": 1,
  "fragments": 2,
  "name": "John SMITH",
  "dateOfBirth": "4/24/1967",
}]

const merged = reportFragments.reduce((acc, curr) => {
  const match = entities.filter(ent => ent.fragments === curr.id);
  return [...acc, ({
    id: curr.id,
    title: curr.title,
    reports: curr.reports,
    ...{
      entities: match
    }
  })]
}, [])

console.log(merged)

​