Python列表，连接2个压缩列表

Question

[('BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5'), ('FIAT 500', 'Mini', '75.48', 'Manual Transmission', 'n/a', '3'), ('VAUXHALL CORSA', 'Economy', ' 79.48', 'Manual Transmission', '5', '5')]
[('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00')]

我有两个压缩列表，我想加入如下：

('BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5', '14.00', '14.99', '39.00')

我怎样才能做到这一点？thx

Answer 1

a = [('BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5'), ('FIAT 500', 'Mini', '75.48', 'Manual Transmission', 'n/a', '3'), ('VAUXHALL CORSA', 'Economy', ' 79.48', 'Manual Transmission', '5', '5')]
b = [('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00')]
[x+y for (x,y) in zip(a,b)]

输出

[('BMW 3 SERIES ESTATE',
  'Premium',
  'GBP 1055.75',
  'Automatic Transmission',
  '5',
  '5',
  '14.00',
  '14.99',
  '39.00'),
 ('FIAT 500',
  'Mini',
  '75.48',
  'Manual Transmission',
  'n/a',
  '3',
  '14.00',
  '14.99',
  '39.00'),
 ('VAUXHALL CORSA',
  'Economy',
  ' 79.48',
  'Manual Transmission',
  '5',
  '5',
  '14.00',
  '14.99',
  '39.00')]

Answer 2

ls1 = [('BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5'), ('FIAT 500', 'Mini', '75.48', 'Manual Transmission', 'n/a', '3'), ('VAUXHALL CORSA', 'Economy', ' 79.48', 'Manual Transmission', '5', '5')]
ls2 = [('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00')]

ans = ls1[0]+ls2[0]
print(ans)

产出：

['BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5', '14.00', '14.99', '39.00']

这就是你想要达到的目标吗？

Answer 3

假设您希望能够将它们全部添加到一起，而不仅仅是第一个元素：

data = [('BMW 3 SERIES ESTATE', 'Premium', 'GBP 1055.75', 'Automatic Transmission', '5', '5'), ('FIAT 500', 'Mini', '75.48', 'Manual Transmission', 'n/a', '3'), ('VAUXHALL CORSA', 'Economy', ' 79.48', 'Manual Transmission', '5', '5')]
nums = [('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00'), ('14.00', '14.99', '39.00')]

for i in range(len(data)):
    data[i] = list(data[i])
    for j in range(len(nums[i])):
        data[i].append(nums[i][j])