进口熊猫为pd进口numpy为np
我有df1、df2和df3三种数据格式。df1=
data = {'Period': ['2024-04-O1', '2024-07-O1', '2024-10-O1', '2025-01-O1', '2025-04-O1', '2025-07-O1', '2025-10-O1', '2026-01-O1', '2026-04-O1', '2026-07-O1', '2026-10-O1', '2027-01-O1', '2027-04-O1', '2027-07-O1', '2027-10-O1', '2028-01-O1', '2028-04-O1', '2028-07-O1', '2028-10-O1'],
'Price': ['NaN','NaN','NaN','NaN', 'NaN','NaN','NaN','NaN', 'NaN','NaN','NaN','NaN',
'NaN','NaN','NaN','NaN', 'NaN','NaN','NaN'],
'years': [2024,2024,2024,2025,2025,2025,2025,2026,2026,2026,2026,2027,2027,2027,2027,2028,
2028,2028,2028],
'quarters':[2,3,4, 1,2,3,4, 1,2,3,4, 1,2,3,4, 1,2,3,4]
}
df1 = pd.DataFrame(data=data)df2=
data = {'price': [473.26,244,204,185, 152, 157],
'year': [2023, 2024, 2025, 2026, 2027, 2028]
}
df3 = pd.DataFrame(data=data)df3=
data = {'quarters': [1,2,3,4],
'weights': [1.22, 0.81, 0.83, 1.12]
}
df2 = pd.DataFrame(data=data)我的目标是计算price of df1。对于通过df1的每一次迭代,检查条件并进行相应的计算。例如,在第一次迭代中,检查df1['year']=2024和df1['quarters']=2.然后是df1['price']=df2.loc[df2['year']=='2024', 'price'] * df3.loc[df3['quarters']==2, 'weights']。
===>>> df1['price'][0]=**473.26*0.81**.
df1['price'][1]=**473.26*0.83**.
...
...
...
and so on.我可以使用这种方法,但我想以更有效的方式编写代码。我想使用以下代码结构。
for i in range(len(df1)):
if (df1['year']==2024) & (df1['quarter']==2):
df1['Price']= df2.loc[df2['year']==2024, 'price'] * df3.loc[df3['quarters']==2, 'weights']
elif (df1['year']==2024) & (df1['quarter']==3):
df1['price']= df2.loc[df2['year']=='2024', 'price'] * df3.loc[df3['quarters']==3, 'weights']
elif (df1['year']==2024) & (df1['quarters']==4):
df1['Price']= df2.loc[df2['year']=='2024', 'price'] * df3.loc[df3['quarters']==4, 'weights']
...
...
...谢谢!
发布于 2022-07-27 16:52:59
我认为,如果我正确理解,您可以首先使用pd.merge将这些字段组合在一起。
df1 = df1.merge(df2, how='left' , left_on='years', right_on='year')
df1 = df1.merge(df3, how='left' , left_on='quarters', right_on='quarters')
df1['Price'] = df1['price']*df1['weights']https://stackoverflow.com/questions/73141730
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