如何将[]字节的字符串转换为[]字节

Question

main.go

package main

import "fmt"

func main() {
    rawString := "Hello World"
    myStringBytes := fmt.Sprint([]byte(rawString))
    
    myResultString := string([]byte(myStringBytes))

    fmt.Println(myResultString)
    fmt.Println(rawString)
}

输出

[72 101 108 108 111 32 87 111 114 108 100]
Hello World

为什么myResultString仍然以字节形式存在？

如何将[]字节的字符串转换为[]字节？

我要myResultString == rawString

Answer 1

只是用这个函数来解决这个问题。Fyi，我使用此方法解析HTML请求中的分号查询参数(：

package main

import (
   "fmt"
   "strconv"
   "strings"
)

func main() {
    rawString := "Hello World"
    myStringBytes := fmt.Sprint([]byte(rawString))
    
    myResultString, _ := string(StringBytesParseString(myStringBytes))

    fmt.Println(myResultString)
    fmt.Println(rawString)
}

func StringBytesParseString(byteString string) (string, error) {
    byteString = strings.TrimSuffix(byteString, "]")
    byteString = strings.TrimLeft(byteString, "[")
    sByteString := strings.Split(byteString, " ")
    var res []byte
    for _, s := range sByteString {
        i, err := strconv.ParseUint(s, 10, 64)
        if err != nil {
            return "", err
        }
        res = append(res, byte(i))
    }

    return string(res), nil
}