如果有三个未知数的话，最好的优化方法？

Question

我编写这段代码是为了作为练习生成一个密码，但我想知道是否有更明智的方法来使用if。我愚蠢地列出了所有可能的案件，我感到很难过。试图将if放在其他if中，这就变得难以理解了。

import random
import re
import exrex

len_pwd = int(input('Length of the password : '))
upc = int(input('Upper case ? (0 = No ; 1 = Yes) : '))
nbr = int(input('Numbers ? (0 = No ; 1 = Yes) : '))
spe = int(input('Special char ? (0 = No ; 1 = Yes) : '))

pwd = ''

for i in range(len_pwd):
    if upc and not nbr and not spe:
        a = exrex.getone('[a-zA-Z]')
        pwd += a
    elif nbr and not upc and not spe:
        a = exrex.getone('[a-z\d]')
        pwd += a
    elif spe and not upc and not nbr:
        a = exrex.getone('[a-z"_$.+-/*=]')
        pwd += a
    elif nbr and spe and not upc:
        a = exrex.getone('[a-z\d"_$.+-/*=]')
        pwd += a
    elif upc and nbr and not spe:
        a = exrex.getone('[a-zA-Z\d]')
        pwd += a
    elif upc and spe and not nbr:
        a = exrex.getone('[a-zA-Z"_$.+-/*=]')
        pwd += a
    elif not upc and not nbr and not spe:
        print("Don't bother me.")
        break
    else:
        a = exrex.getone('[a-zA-Z\d"_$.+-/*=]')
        pwd += a

print(pwd)

谢谢！另外，如果代码中还有什么是麻利的，请告诉我:)

Answer 1

您可以根据输入构建regex字符串：

reg = '[a-z'
if upc: reg += "A-Z"
if nbr: reg += "\\d"
if spe: reg += "_$.+-/*="
reg += "]"