如何声明GlyphRun对象？

Question

我只需要画几个数字。仅仅定义GlyphRun和FontRenderingEmSize就足够了吗？如果没有，请建议我如何绘制字符串"123“(如何定义GlyphRun对象)。我写了这段代码：

var gr = new GlyphRun();
gr.Characters = new List<char>() { '1', '2' }; //Mistake
gr.FontRenderingEmSize = 20;
var Glyph = new GlyphRunDrawing(Brushes.Black, gr);

Answer 1

我找到了我的一个老帮手班。也许你可以利用它。

public static class GlyphRunText
{
    public static GlyphRun Create(
        string text, Typeface typeface, double emSize, Point baselineOrigin)
    {
        GlyphTypeface glyphTypeface;

        if (!typeface.TryGetGlyphTypeface(out glyphTypeface))
        {
            throw new ArgumentException(string.Format(
                "{0}: no GlyphTypeface found", typeface.FontFamily));
        }

        var glyphIndices = new ushort[text.Length];
        var advanceWidths = new double[text.Length];

        for (int i = 0; i < text.Length; i++)
        {
            var glyphIndex = glyphTypeface.CharacterToGlyphMap[text[i]];
            glyphIndices[i] = glyphIndex;
            advanceWidths[i] = glyphTypeface.AdvanceWidths[glyphIndex] * emSize;
        }

        return new GlyphRun(
            glyphTypeface, 0, false, emSize,
            glyphIndices, baselineOrigin, advanceWidths,
            null, null, null, null, null, null);
    }
}