：'dpi‘

Question

我有一个python脚本，它列出了目录中照片的元数据。它起作用了，但是它还没有完全发挥作用。当它运行时，我可以从大约250个文件中获取数据，然后得到一个错误。

这是一个错误：

  File "c:\Users\edward\OneDrive - ISC Industries\Summer Intern 2022\Scripts\metadata.py", line 22, in <module>
"Image DPI": image.info['dpi'],
KeyError: 'dpi'

我不知道这是为什么，因为它工作的一些文件，但有超过17000份文件，所以我希望所有的数据被打印。

下面是完整的脚本：

import json
from PIL import Image
from PIL.ExifTags import TAGS
import os
import os.path
import PIL
from pandas import json_normalize

PIL.Image.MAX_IMAGE_PIXELS = 384000000
rootdir = r"C:\Users\edward\OneDrive\Pics"

newfile = newfile = open('meta.txt', 'w')
newfile.write("Filename                                     |  Image DPI                    | Image Height                  |   Image Width                 |   Image Format                |   Image Mode                  |   Image Frames                |\n")
for file in os.listdir(rootdir):
    # read the image data using PIL
    image = Image.open(os.path.join(rootdir, file))

# extract other basic metadata
info_dict = {
    "Filename": image.filename,
    "Image DPI": image.info['dpi'],
    "Image Height": image.height,
    "Image Width": image.width,
    "Image Format": image.format,
    "Image Mode": image.mode,
    "Frames in Image": getattr(image, "n_frames", 1)
}

line = ""
for label, value in info_dict.items():
    line += f"|{str(value):<30} "  
line += " |"  
newfile.write(line + '\n')

谢谢

Answer 1

您可以使用try和except，只需重用您的代码：

for file in os.listdir(rootdir):
try:
    # read the image data using PIL
    image = Image.open(os.path.join(rootdir,file))

    # extract other basic metadata
    info_dict = {
        "Filename": os.path.basename(image.filename),
        "Image DPI": image.info['dpi'],
        "Image Height": image.height,
        "Image Width": image.width,
        "Image Format": image.format,
        "Image Mode": image.mode,
        "Frames in Image": getattr(image, "n_frames", 1)
    }

    line = ""
    for label, value in info_dict.items():
        line += f"|{str(value):<30} "  
    line += " |"  
    newfile.write(line + '\n')
except:
    # read the image data using PIL
    image = Image.open(os.path.join(rootdir,file))

    # extract other basic metadata
    info_dict = {
        "Filename": os.path.basename(image.filename),
        "Image Height": image.height,
        "Image Width": image.width,
        "Image Format": image.format,
        "Image Mode": image.mode,
        "Frames in Image": getattr(image, "n_frames", 1)
    }

    line = ""
    for label, value in info_dict.items():
        line += f"|{str(value):<30} "  
    line += " |"  
    newfile.write(line + '\n')