上一次我用新的GCC12编译了我的项目,它给了我关于内存缓冲区大小错误的警告。此前版本的GCC没有报道过这样的警告。
介绍我的情况的简单代码示例:
#include <vector>
#include <cstdint>
#include <iostream>
struct [[gnu::packed]] S {
uint32_t a;
uint8_t b;
uint16_t c;
};
std::vector<uint8_t> s_to_bytes(const S &s) {
S x = s;
std::vector<uint8_t> res;
res.insert
( res.begin()
, reinterpret_cast<uint8_t*>(&x)
, reinterpret_cast<uint8_t*>(&x) + sizeof(S)
);
return res;
}
int main () {
S s{1,2,3};
auto bytes = s_to_bytes(s);
for (auto &x : bytes) std::cout << static_cast<int>(x) << " ";
std::cout << std::endl;
return 0;
} 当我通过G++12命令编译这段代码时
g++ -Wall -Wextra -O2 -Wpedantic -std=c++20 invalid_optimization.cpp它打印警告:
inlined from ‘std::vector<unsigned char> s_to_bytes(const S&)’ at invalid_optimization.cpp:16:5:
/usr/include/c++/12/bits/stl_algobase.h:431:30: warning: ‘void* __builtin_memmove(void*, const void*, long unsigned int)’ writing 1 or more bytes into a region of size 0 overflows the destination [-Wstringop-overflow=]
431 | __builtin_memmove(__result, __first, sizeof(_Tp) * _Num);
| ~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
In member function ‘_Tp* std::__new_allocator<_Tp>::allocate(size_type, const void*) [with _Tp = unsigned char]’,
inlined from ‘constexpr _Tp* std::allocator< <template-parameter-1-1> >::allocate(std::size_t) [with _Tp = unsigned char]’ at /usr/include/c++/12/bits/allocator.h:183:40,
inlined from ‘static constexpr _Tp* std::allocator_traits<std::allocator<_Up> >::allocate(allocator_type&, size_type) [with _Tp = unsigned char]’ at /usr/include/c++/12/bits/alloc_traits.h:464:28,
inlined from ‘constexpr std::_Vector_base<_Tp, _Alloc>::pointer std::_Vector_base<_Tp, _Alloc>::_M_allocate(std::size_t) [with _Tp = unsigned char; _Alloc = std::allocator<unsigned char>]’ at /usr/include/c++/12/bits/stl_vector.h:378:33,
inlined from ‘constexpr std::_Vector_base<_Tp, _Alloc>::pointer std::_Vector_base<_Tp, _Alloc>::_M_allocate(std::size_t) [with _Tp = unsigned char; _Alloc = std::allocator<unsigned char>]’ at /usr/include/c++/12/bits/stl_vector.h:375:7,
inlined from ‘constexpr void std::vector<_Tp, _Alloc>::_M_range_insert(iterator, _ForwardIterator, _ForwardIterator, std::forward_iterator_tag) [with _ForwardIterator = unsigned char*; _Tp = unsigned char; _Alloc = std::allocator<unsigned char>]’ at /usr/include/c++/12/bits/vector.tcc:787:40,
inlined from ‘constexpr void std::vector<_Tp, _Alloc>::_M_insert_dispatch(iterator, _InputIterator, _InputIterator, std::__false_type) [with _InputIterator = unsigned char*; _Tp = unsigned char; _Alloc = std::allocator<unsigned char>]’ at /usr/include/c++/12/bits/stl_vector.h:1779:19,
inlined from ‘constexpr std::vector<_Tp, _Alloc>::iterator std::vector<_Tp, _Alloc>::insert(const_iterator, _InputIterator, _InputIterator) [with _InputIterator = unsigned char*; <template-parameter-2-2> = void; _Tp = unsigned char; _Alloc = std::allocator<unsigned char>]’ at /usr/include/c++/12/bits/stl_vector.h:1481:22,
inlined from ‘std::vector<unsigned char> s_to_bytes(const S&)’ at invalid_optimization.cpp:16:5:
/usr/include/c++/12/bits/new_allocator.h:137:55: note: at offset 7 into destination object of size 7 allocated by ‘operator new’
137 | return static_cast<_Tp*>(_GLIBCXX_OPERATOR_NEW(__n * sizeof(_Tp)));此警告显示,进入向量的insert被优化为__builtin_memmove(__result, __first, sizeof(_Tp) * _Num);调用,但大小无效。向量insert文档告诉我们,插入是在范围[first, last)中执行的,所以结构指针的末尾必须指向结构之后的下一个字节,就像迭代器.end()一样,但是GCC从这个有效的代码中进行了无效的memmove调用,它可能得到了结构大小+1,而不仅仅是结构大小。看起来__builtin_memmove只是first和last指针的不同,而不是last - first - 1。
我的问题是:我的vector::insert使用是无效的还是GCC12优化错误?
发布于 2022-07-05 09:51:07
我的问题是:我的
vector::insert使用是无效的还是GCC12优化错误?
正如评论中提到的,这是gcc的一个警告错误。减缩
#include <vector>
#include <array>
std::vector<int> s_to_bytes() {
std::vector<int> res;
std::array<int, 4> s{};
res.insert(res.begin(), s.begin(), s.end());
return res;
}上面的代码无疑是格式良好的,但是gcc-12给出了一个意外的__builtin_memmove溢出警告。
Bug提交了106199。
https://stackoverflow.com/questions/72867072
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