如何使用Javascript将乘客分配到航班上

Question

我有一个项目，负责管理航班和乘客号码。我现在正忙于实现下面的函数，任何关于我如何去做的建议都是很棒的，我现在所拥有的是我认为不正确的，再次感谢。

问题：

在旅客()函数中，编写一个distributeAllSeatsToAllPassengers()函数，作为参数接收贵宾人数、常规乘客人数、航班数目、每次航班商务座位数和每次航班经济舱座位数。返回包含以下字段的对象:带商务座位的VIP乘客；带经济座位的VIP乘客；带商务座位的普通乘客；带经济座位的普通乘客。

必须按照以下顺序遵守分配规则：

首先，将贵宾乘客分配到商务座位上，直到VIP乘客或商务座位被消费为止。

然后，如果仍然有贵宾乘客，将他们分配到经济座位，直到贵宾乘客或经济座位被消费。

然后，如果仍然有商务座位，则将普通乘客分配到商务座位上，直到正式乘客或商务座位被消费为止。

然后，如果仍然有经济座位，就把普通乘客分配到经济座位上，直到普通乘客或经济座位被消费为止。你必须指派尽可能多的乘客。可能有乘客，也可能还有剩下的座位。

定义distributeAllSeatsToAllPassengers()函数后，一行代码将从模块导出函数:返回{distributeAllSeatsToAllPassengers}；

当前解决方案：

import { supportsEsModules } from "mocha/lib/utils";

function Passengers() {

    function distributeAllSeatsToAllPassengers(vipPassengers, 
        regularPassengers, nrOfFlights, businessSeatsPerFlight, economySeatsPerFlight)
    { 
        let vipPassengersAssignedToBusinessSeats = 0;
        let vipPassengersAssignedToEconomySeats = 0;
        let regularPassengersAssignedToBusinessSeats = 0;

        vipPassengersAssignedToBusinessSeats = vipPassengers / businessSeatsPerFlight;
        vipPassengersNotSeated = vipPassengers % businessSeatsPerFlight;
        
        
        if (vipPassengersNotSeated !== 0)
        {
            vipPassengersAssignedToEconomySeats = vipPassengersNotSeated / economySeatsPerFlight;
            vipPassengersStillNotSeated = vipPassengersNotSeated % economySeatsPerFlight;
        }

        if (businessSeatsPerFlight !== 0)
        {
            regularPassengersAssignedToBusinessSeats = regularPassengers / businessSeatsPerFlight;
            regularPassengersNotSeated = regularPassengers % businessSeatsPerFlight;
        }

        if (economySeatsPerFlight !== 0)
        {
            regualarPassengersAssignedToEconomySeats = regularPassengersNotSeated / economySeatsPerFlight;
            regularPassengersStillNotSeated = regularPassengersNotSeated % economySeatsPerFlight;
        }

        var distributedPassengers = {
            vipPassengersWithBusinessSeats: vipPassengersAssignedToBusinessSeats,
            vipPassengersWithEconomySeats: vipPassengersAssignedToEconomySeats,
            regularPassengersWithBusinessSeats: regularPassengersAssignedToBusinessSeats,
            regularPassengersWithEconomySeats: regularPassengersAssignedToEconomySeats
        };
        return { distributedPassengers };

    }
    return { distributeAllSeatsToAllPassengers };
}

module.exports = Passengers();

Answer 1

这就是我想出来的，我不知道这是否符合你们老师的指导原则，但应该有效。也许可以作为一个起点。我补充了解释。

行vipPassengersAssignedToBusinessSeats = vipPassengers / businessSeatsPerFlight;的问题是，您可能会得到一个浮点数。图片有3个贵宾乘客和2个商务座位- 3/2返回一个花车。我会用循环来解决这个问题。

免责声明:没有测试，我以前也没有使用过%操作符，但我相信你可以适应。

function Passengers() {

function distributeAllSeatsToAllPassengers(num_flights, economy_seats, business_seats, passengers_vip, passengers_regular) {

    // number of flights is completely redundant in this example
    
    let passengers_vip_seated_business = 0,
        passengers_vip_seated_economy = 0,
        passengers_regular_seated_business = 0,
        passengers_regular_seated_economy = 0,
        passengers_vip_unseated = 0, // not necessary but nice to have
        passengers_economy_unseated = 0; // see above

    // use a for..of loop, assuming passengers_vip is an array
    for (let passenger of passengers_vip) {
        if (business_seats > 0) {
            business_seats--; // reduce number of available business seats
            passengers_vip_seated_business++; // increase number of seated passengers
        } else if (economy_seats > 0) {
            // if there are no business seats available, assign to economy_seats
            economy_seats--;
            passengers_vip_seated_economy++;
        } else {
            // no more seats, bummer!
            passengers_vip_unseated++;
        }
    }
    // do the same for regular passengers
    for (let passenger of passengers_regular) {
        if (business_seats > 0) {
            business_seats--; // reduce number of available business seats
            passengers_regular_seated_business++; // increase number of seated passengers
        } else if (economy_seats > 0) {
            // if there are no business seats available, assign to economy_seats
            economy_seats--;
            passengers_regular_seated_economy++;
        } else {
            // no more seats, bummer!
            passengers_economy_unseated++;
        }
    }
    
    return {
        passengers_vip_seated_business: passengers_vip_seated_business,
        passengers_vip_seated_economy: passengers_vip_seated_economy,
        passengers_regular_seated_business: passengers_regular_seated_business,
        passengers_regular_seated_economy: passengers_regular_seated_economy
    }
}

// returns the function, idk why but okay, maybe for functional programming
return {distributeAllSeatsToAllPassengers}
}