txt =“”.join(如果c不在string.punctuation中则为txt中的c=c)和TypeError：‘string.punctuation’对象不可迭代

Question

有点奇怪。我有许多excel文件，每个文件中有超过50万个数据点。有些文件我可以删除停止和进行柠檬化，大多数文件都会出现以下错误

txt = "".join([c for c in txt if c not in string.punctuation])

TypeError：“浮点”对象不可迭代

感谢你的任何帮助

import nltk
wn = nltk.WordNetLemmatizer()
ps = nltk.PorterStemmer()
dir(wn)

import pandas as pd
import re
import string
from nltk.corpus import stopwords
pd.set_option ("display.max_colwidth", 200)
stop_word = set(stopwords.words("english"))
excel_path = (r"C:xxxx-BTC 21-30-4.xlsx")
data = pd.read_excel(excel_path)
data.columns = ["#","id", "date","Name","text_4"]


#clean text

def clean_text(txt) :
   txt = "".join([c for c in txt if c not in string.punctuation])
   tokens = re.split('\W+',txt)
   txt = [word for word in tokens if word not in stop_word]
   return txt

    data['text_5'] = data['text_4'].apply(lambda x: clean_text(x))
    #print(data.head)
#lemmatization

def lemmatization(tolken_txt):
    text = [wn.lemmatize(word) for word in tolken_txt]
    return text
data["text_6"] = data['text_5'].apply(lambda x: lemmatization(x))

print(data.head)

Answer 1

你好，如果您确信列data['text_4']中没有浮点，则可能缺少不能交互的值。试着用"“来表示或填充。祝好运。